函数实现实现两个数组的交并差集

结果如图：

输入数组

操作：

#include <iostream>
using namespace std;
int m;
int n;
void jiao(int *a,int *b){
	int flag;
	for(int i=0 ;i<m;i++){
		flag=0;
		for(int j=0 ;j<n;j++){
			if(a[i]==b[j]){
				flag=1;
				break;
			}
		} 
		if(flag==1)
		cout<<a[i]<<"  ";
	} 
}
void bing(int a[],int b[]){
	for(int i=0;i<n;i++){
		cout<<b[i]<<"  ";
	}
	int flag;
	for(int i=0 ;i<m;i++){
		flag=0;
		for(int j=0 ;j<n;j++){
			if(a[i]==b[j]){
				flag=1;
				break;
			}
		} 
		if(flag==0)
		cout<<a[i]<<"  ";
	}
}
void cha(int a[],int b[]){
	int flag;
	for(int i=0 ;i<m;i++){
		flag=0;
		for(int j=0 ;j<n;j++){
			if(a[i]==b[j]){
				flag=1;
				break;
			}
		} 
		if(flag==0)
		cout<<a[i]<<"  ";
	}
}
int main(){	
	cout<<"请输入第一个数组a的长度"<<endl; 
	cin>>m;
	int *a = NULL;
	a = new int[m];
	cout<<"请输入数组的"<<m<<"个元素"<<endl;
	for(int i=0;i<m;i++)
	cin>>a[i];
	cout<<"请输入第二个数组b的长度"<<endl;
	cin>>n;
	int *b = NULL;
	b = new int[n];
	cout<<"请输入数组的"<<n<<"个元素"<<endl;
	for(int i=0;i<n;i++)
	cin>>b[i];
	int s;
	while(1){
		cout<<"1.输出交集:"<<endl;
		cout<<"2.输出并集为:"<<endl;
		cout<<"3.输出a-b差集为:"<<endl;
		cout<<"0.退出成功!"<<endl;
		cin>>s;
		switch(s){
			case 1:cout<<"交集为:";jiao(a,b);cout<<endl;break;
			case 2:cout<<"并集为:";bing(a,b);cout<<endl;break;
			case 3:cout<<"a-b差集为:";cha(a,b);cout<<endl;break;
			case 0:cout<<"退出成功!"<<endl;return 0; 
		}
	}
}