PHP数组从一个数组合并到另一个数组中的值

Question

对不起，我已阅读了这么多帖子来理解这一点，并最终让我自己感到困惑！

我有2列：

阵列1：

Array (

[0] => Array ([ID] => SI[Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.188875 [Tier2] => [Tier3] => [Tier4] => [Delivery] => 0) 

[1] => Array ([ID] => SI[Date] => 06/01/2016 [Month] => 1 [Tier1] => 2.139 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0) 

[2] => Array ([ID] => SI[Date] => 14/01/2016 [Month] => 1 [Tier1] => 0.201 [Tier2] => 0 [Tier3] => 0 [Tier4] => 0 [Delivery] => 0) 

) 

阵列2：（包含与送货费的发票）

Array ( 
[SI000005] => 25 
[SI000010] => 15 
[SI000054] => 20 
[SI000069] => 0 
[SI000074] => 20 
[SI000076] => 16 
) 

我需要在那里SI00000x匹配更新阵列1并将数组2中的值推入数组1中的[Delivery]值。

我是确定这是直截​​了当的，但我尝试的任何事情都需要一个年龄或崩溃！

请帮忙！

Answer 1

您可以使用此（注意ampersand）：

foreach ($arr1 as &$rec) { 
    if (isset($arr2[$rec['ID']])) $rec['Delivery'] = $arr2[$rec['ID']]; 
} 

Answer 2

foreach ($array1 as &$a1) { 
    if (isset($array2[$a1['ID']])) { 
     $a1['Delivery'] = $array2[$a1['ID']]; 
    } 
} 

Answer 3

试试这个（使用参考）

foreach ($array1 as &$a1) { 
    if(isset($array1[$a1['ID']])) $a1['Delivery'] = $array1[$a1['ID']]; 
}