spring jquery ajax 无刷新传递form整个表单给一个下拉框增加一个选项 并选中

后台的代码：

@RequestMapping("/mysaveClient")
public @ResponseBody MapmysaveClient(@ModelAttribute Client
client) {
  Client client=myProjectApplicationService.saveClient(client);
  Map josnMap = new HashMap();

Map clientMap=new HashMap();
  clientMap.put("id", client.getId());
  clientMap.put("name", client.getname());
List list=new ArrayList();  

list.add(clientMap);
josnMap.put("clients",list);
return
josnMap;
}

ajax的代码如下：
$("#save_client").click(function(){
          $.ajax({    
   url: "${pageContext.request.contextPath}/mysaveClient",
data:  $('#form_client').serialize(),
success:function(data){
$("#myWrap").hide();

$.each(data.clients, function(index,item){

 $("#projectArtical_client_id").append('<option value='+item.id+'>'+item.specification+'</option>')

if(data == "ok") {
$.messager.alert("提示","权限修改成功！");
}
}
});
return false;
});  
前端代码：