php解析json数据

问题描述：

从来没有这样做过，并且对格式和如何访问特定变量感到困惑。php解析json数据

结果：

$result = json_decode($result); 
print_r($result);

是：

stdClass Object 
(
    [input] => stdClass Object 
     (
      [address_components] => stdClass Object 
       (
        [number] => 1109 
        [predirectional] => N 
        [street] => Highland 
        [suffix] => St 
        [formatted_street] => N Highland St 
        [city] => Arlington 
        [state] => VA 
        [zip] => 22201 
        [country] => US 
       ) 

      [formatted_address] => 1109 N Highland St, Arlington, VA 22201 
     ) 

    [results] => Array 
     (
      [0] => stdClass Object 
       (
        [address_components] => stdClass Object 
         (
          [number] => 1109 
          [predirectional] => N 
          [street] => Highland 
          [suffix] => St 
          [formatted_street] => N Highland St 
          [city] => Arlington 
          [county] => Arlington County 
          [state] => VA 
          [zip] => 22201 
          [country] => US 
         ) 

        [formatted_address] => 1109 N Highland St, Arlington, VA 22201 
        [location] => stdClass Object 
         (
          [lat] => 38.886672 
          [lng] => -77.094735 
         ) 

        [accuracy] => 1 
        [accuracy_type] => rooftop 
        [source] => Arlington 
       ) 

      [1] => stdClass Object 
       (
        [address_components] => stdClass Object 
         (
          [number] => 1109 
          [predirectional] => N 
          [street] => Highland 
          [suffix] => St 
          [formatted_street] => N Highland St 
          [city] => Arlington 
          [county] => Arlington County 
          [state] => VA 
          [zip] => 22201 
          [country] => US 
         ) 

        [formatted_address] => 1109 N Highland St, Arlington, VA 22201 
        [location] => stdClass Object 
         (
          [lat] => 38.886665 
          [lng] => -77.094733 
         ) 

        [accuracy] => 1 
        [accuracy_type] => rooftop 
        [source] => Virginia Geographic Information Network (VGIN) 
       ) 

     ) 

)

我如何可以访问纬度和经度值？由于混合了对象和数组，因此我感到困惑。我从来没有用这种方式与PHP的JSON合作...这是一个地理编码api，返回JSON格式。

我基本上想要做一些类似$lat = $result['results'][0]['location']['lat'];等等。

使用类型转换，将其转换成对象 –

答

你必须json_decode使用true作为第二个参数，以便输出将是正常的PHP数组不stdclass阵列（这样就可以用你的方法，你正在尝试什么）

所以做象下面这样： -

$result = json_decode($result,true); 

echo $lat = $result['results'][0]['location']['lat']; 
echo $lng = $result['results'][0]['location']['lng'];

注： -

1.根据您目前的格式，也可以得到数据如下图所示： -

echo $lat = $result->results[0]->location->lat; //using object approach 
echo $lng = $result->results[0]->location->lng; //using object approach

2.使用foreach()让所有lat-lng记录。

foreach($result->results as $val) { //if using stdclass array 
    echo "Latitude = ".$val->location->lat; 
    echo "Longitude = ".$val->location->lng; 
}

或者： -

foreach($result['results'] as $val) {//if using normal array 
    echo "Latitude = ".$val['location']['lat']; 
    echo "Longitude = ".$val['location']['lng']; 
}

知道它是一些简单的我失踪了......这就是我一直在寻找...谢谢！ – user756659

@ user756659很高兴帮助你:) :) –

答

使用第二个参数为转换所有对象数组为真。否则，你可以得到这样的值。

$result->results[0]->location->lat; 
$result->results[0]->location->lng;

这是'lng'不''长'。现在+1，因为你也是正确的。 –

答

您可以从结果存取纬度经度如下

$result = json_decode($result); 
echo $result->results[0]->location->lat; 
echo $result->results[0]->location->lng;

答

我可以看到，从你的榜样，你有多个记录来获取。使用foreach()打印细节

$result = json_decode($result); 
foreach($result->results as $value) { 
    echo "Lat--",$value->location->lat; //using object 
    echo "Long--",$value->location->lng; 
}

php解析json数据

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