获取从包含特定字符串

Question

对象属性我有一个这样的对象：

v = { 
    x1: "x", 
    x1_trust: "y", 
    x2: "something", 
    x2_trust: "something_else" 
} 

是否有可能创建一个包含“_trust”属性的新对象？我不知道该怎么做。

Answer 1

您可以使用Object.keys()和reduce()创建新对象，并使用indexOf()来检查对象键是否包含子字符串。

var v = { 
 
    x1: "x", 
 
    x1_trust: "y", 
 
    x2: "something", 
 
    x2_trust: "something_else" 
 
} 
 

 
var newObj = Object.keys(v).reduce(function(r, key) { 
 
    if (key.indexOf('_trust') != -1) r[key] = v[key]; 
 
    return r; 
 
}, {}); 
 

 
console.log(newObj)

Answer 2

使用Array#reduce超过Object.keys

var v = { 
 
    x1: "x", 
 
    x1_trust: "y", 
 
    x2: "something", 
 
    x2_trust: "something_else" 
 
}; 
 

 
var op = Object.keys(v).reduce(function(a, b) { 
 
    return (b.indexOf('_trust') > -1) && (a[b] = v[b]), a; 
 
}, {}); 
 

 
console.log(op);

Answer 3

你想让它只有_trust从你的对象V截取密钥和值的新对象？ 如果是这种情况，请尝试此代码（使用jquery）

v = { 
    x1: "x", 
    x1_trust: "y", 
    x2: "something", 
    x2_trust: "something_else" 
} 

var newJson = {}; 
jQuery.each(v, function(key, val) { 
    if(key.indexOf("_trust") > -1){ 
     newJson[key] = val; 
    } 
});