CCF 2017-9-1 打酱油 python实现
n=input()
n=eval(n)
battle=n/10
def count(a):
if 2*(a//5)+a%5//3>=a//3:
return 2*(a//5)+a%5//3
else:
return a//3
count=battle+count(battle)
print('{:.0f}'.format(count))
n=input()
n=eval(n)
battle=n/10
def count(a):
if 2*(a//5)+a%5//3>=a//3:
return 2*(a//5)+a%5//3
else:
return a//3
count=battle+count(battle)
print('{:.0f}'.format(count))