Python 3岩石，纸张，剪刀问题

Question

我正在编写一个编程作业，并且遇到了一个小小的障碍，我正在为一个岩石，纸张，剪刀游戏工作。该程序假设由用户选择4个选项中的1个，1）摇滚，2）纸，3）剪刀和4）退出。一旦玩家选择了一个选项，计算机的选择就会显示出来，获胜者将被宣布，程序会询问你是否想玩另一个游戏。如果选择y，则返回主菜单选择另一个选项，其他任何选项都会显示赢得的比赛数量，丢失的比赛以及比赛结束时的比赛数量。如果玩家选择4，则该程序应该说“退出程序...”，并且应该显示游戏结果。

这里是我的问题：

1. 一旦你做出了第一个选择，显示赢家和程序返回到主菜单。如果您再次选择，它会通知您电脑选择的内容，然后询问您是否想再次播放。 Y会带你回到主菜单，电脑的选择永远不会改变，无论你选择什么游戏，总是会以与第一场比赛相同的结果结束。如果您选择不再玩，那么会出现赢，输和游戏的数量（这似乎是正常运行）。

2. 退出选项会将您带回主菜单，而不是显示游戏结果。我不知道该在哪里发表声明。

任何有关这些问题的帮助，将不胜感激。

谢谢

#import module 
import random 

def main(): 
    #create a variable to control the loop 
    play_again = 'y' 

    #create a counter for tied games, computer games and player games 
    tied_games = 0 
    computer_games = 0 
    player_games = 0 

    #display opening message 
    print("Let's play rock, paper scissors!") 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 

    winner = determine_winner(player_choice, computer_choice) 

    #setup while loop for playing multiple games 
    while play_again == 'y' or play_again == 'Y': 

     process_computer_choice() 

     process_player_choice() 

     #use a if else statement to print the computers choice 
     if computer_choice == 1: 
      print('computer chooses rock.') 

     elif computer_choice == 2: 
      print('computer chooses paper.') 

     else: 
      print('computer chooses scissors.') 

      #call the determine winner function  
      determine_winner(player_choice, computer_choice) 

     #check who won the game and add 1 to the correct counter 
     if winner == 'computer': 
      computer_games += 1 

     elif winner == 'player': 
      player_games += 1 

     else: 
      tied_games += 1 

     #ask the user if they would like to play again  
     play_again = input('would you like to play again? (enter y for yes): ') 

    #display number of games that were won by the computer, the player and that were tied 
    print() 
    print('there was', tied_games, 'tied games.') 
    print('the player won', player_games, 'games.') 
    print('The computer won', computer_games,'games.') 

#define the process computer function 
def process_computer_choice(): 

    #setup computer to select random integer between 1 and 3 
    choice1 = random.randint(1, 3) 

    #return the computers choice 
    return choice1 

#define the process player function 
def process_player_choice(): 

    #add input for players choice 
    print() 
    print('  MENU') 
    print('1) Rock!') 
    print('2) Paper!') 
    print('3) Scissors!') 
    print('4) Quit') 
    print() 

    player_choice = int(input('Please make a selection: ')) 

    #add if statement for quit option 
    if player_choice == 4: 
     print('Exiting program....') 

    #validate if the user enters a correct selection 
    while player_choice != 1 and player_choice != 2 and player_choice != 3 and player_choice != 4: 

     #print a error message if the wrong selection is entered 
     print('Error! Please enter a correct selection.') 

     player_choice = int(input('Please make a selection: ')) 

    #return the players choice 
    return player_choice 

#define the determine winner function 
def determine_winner(player_choice, computer_choice): 

    #setup if else statements for each of the 3 computer selections 
    if computer_choice == 1: 
     if player_choice == 2: 
      print('Paper wraps rock. You win!') 
      winner = 'player' 

     elif player_choice == 3: 
      print('Rock smashes scissors. The computer wins!') 
      winner = 'computer' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    if computer_choice == 2: 
     if player_choice == 1: 
      print('Paper wraps rock. The computer wins!') 
      winner = 'computer' 

     elif player_choice == 3: 
      print('Scissors cut paper. You win!') 
      winner = 'player' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    if computer_choice == 3: 
     if player_choice == 1: 
      print('Rock smashes scissors. You win!') 
      winner = 'player' 

     elif player_choice == 2: 
      print('Scissors cut paper. The computer wins!') 
      winner = 'computer' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    return winner 

main() 

Answer 1

对于问题1，这是因为您在循环之前设置的计算机和球员的选择，从不更新它们。你的循环的开始更改为：

while play_again == 'y' or play_again == 'Y': 
    computer_choice = process_computer_choice() 
    player_choice = process_player_choice() 

另外，还可以检查输入的赢家，因为它是第一轮技术上冗余环路之前删除的代码行。

对于问题2，只需添加结果选择了4后，像这样：

if player_choice == 4: 
     print('Exiting program....') 
     print('there was', tied_games, 'tied games.') 
     print('the player won', player_games, 'games.') 
     print('The computer won', computer_games,'games.') 
     sys.exit() # be sure you add 'import sys' to the beginning of your file 

此外，线路在主回路determine_winner(player_choice, computer_choice)缩进所以它才会被调用，如果计算机选择剪刀，所以你应该unindent：:)

Answer 2

您还没有分配给computer_choice或player_choice一遍，但使用它的价值。

while play_again == 'y' or play_again == 'Y': 

    process_computer_choice() 

    process_player_choice() 

应该

while play_again == 'y' or play_again == 'Y': 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 

至于退出只是在退出选择突破。您必须尽早从process_player_choice返回，并在main中执行一些操作。

所以在process_player_choice：

if player_choice == 4: 
    print('Exiting program....') 
    return 

，并在主： player_choice = process_player_choice（）

if player_choice == 4: 
    return 

winner = determine_winner(player_choice, computer_choice) 

#setup while loop for playing multiple games 
while play_again == 'y' or play_again == 'Y': 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 
    if player_choice == 4: 
     break