SQL在多个表中选择，每个连接表中的最大日期为

Question

我有一个Oracle 11 SQL查询，我从4个表中抽取所有由ID连接的数据。加入第一个表的每个表都有一个ACTIVE_IND值，该值必须是'Y'和生效日期（EFF_DATE），并且我需要每个记录的生效日期最长。

我有一个查询，在这里工作，但想知道是否有一个更优化/有效/有效的方式写它，因为它似乎有点慢。我目前使用这样看起来是什么：

SELECT DISTINCT A.TABLE1_ID, 
       A.TABLE1_COL1, 
       B.TABLE2_COL2, 
       C.TABLE3_COL3, 
       D.TABLE4_COL4 
FROM TABLE1 A, 
    TABLE2 B, 
    TABLE3 C, 
    TABLE4 D 
WHERE B.TABLE2_ID = A.TABLE1_ID 
    AND B.TABLE2_ACTIVE_IND = 'Y' 
    AND B.TABLE2_EFF_DATE = 
    (SELECT MAX (B2.TABLE2_EFF_DATE) 
    FROM TABLE2 B2 
    WHERE B2.TABLE2_ID = B.TABLE2_ID 
     AND B2.TABLE2_ACTIVE_IND = 'Y') 
    AND C.TABLE3_ID = A.TABLE1_ID 
    AND C.TABLE3_ACTIVE_IND = 'Y' 
    AND C.TABLE3_EFF_DATE = 
    (SELECT MAX (C2.TABLE3_EFF_DATE) 
    FROM TABLE3 C2 
    WHERE C2.TABLE3_ID = C.TABLE3_ID 
     AND C2.TABLE3_ACTIVE_IND = 'Y') 
    AND D.TABLE4_ID = A.TABLE1_ID 
    AND D.TABLE4_ACTIVE_IND = 'Y' 
    AND D.TABLE4_EFF_DATE = 
    (SELECT MAX (D2.TABLE4_EFF_DATE) 
    FROM TABLE4 D2 
    WHERE D2.TABLE4_ID = D.TABLE4_ID 
     AND D2.TABLE4_ACTIVE_IND = 'Y') 
ORDER BY A.TABLE1_ID; 

Answer 1

尝试：

SELECT DISTINCT A.TABLE1_ID, 
       A.TABLE1_COL1, 
       B.TABLE2_COL2, 
       C.TABLE3_COL3, 
       D.TABLE4_COL4 
FROM TABLE1 A 
JOIN (SELECT T2.*, 
      RANK() OVER (PARTITION BY TABLE2_ID ORDER BY TABLE2_EFF_DATE DESC) RN 
     FROM TABLE2 T2 
     WHERE TABLE2_ACTIVE_IND = 'Y') B ON B.TABLE2_ID = A.TABLE1_ID AND B.RN=1 
JOIN (SELECT T3.*, 
      RANK() OVER (PARTITION BY TABLE3_ID ORDER BY TABLE3_EFF_DATE DESC) RN 
     FROM TABLE3 T3 
     WHERE TABLE3_ACTIVE_IND = 'Y') C ON C.TABLE3_ID = A.TABLE1_ID AND C.RN=1 
JOIN (SELECT T4.*, 
      RANK() OVER (PARTITION BY TABLE4_ID ORDER BY TABLE4_EFF_DATE DESC) RN 
     FROM TABLE4 T4 
     WHERE TABLE4_ACTIVE_IND = 'Y') D ON D.TABLE4_ID = A.TABLE1_ID AND D.RN=1 
ORDER BY A.TABLE1_ID;