llvm获得注释
问题描述:
我更新了我的上一个问题在一个新的形式。 大家好,llvm获得注释
我有以下LLVM IR:
@.str = private unnamed_addr constant [3 x i8] c"DS\00", section "llvm.metadata"
@llvm.global.annotations = appending global [1 x { i8*, i8*, i8*, i32 }] [{ i8*, i8*, i8*, i32 } { i8* bitcast (i32* @f to i8*), i8* getelementptr inbounds ([3 x i8]* @.str, i32 0, i32 0), i8* getelementptr inbounds ([9 x i8]* @.str1, i32 0, i32 0), i32 18 }], section "llvm.metadata"
我需要得到@f
(或者也许我能得到某种方式的@f = global i32 0, align 4
的定义),也是我需要从@.str
获得“DS” 。在我的目标代码,我有:
__attribute__((annotate("DS"))) int f=0;
我有问题解析@ llvm.global.annotations,我以为我会与@名为.str。我的尝试:
1.
for (Module::global_iterator I = F.global_begin(), E = F.global_end(); I != E; ++I) {
if (I->getName() == "llvm.global.annotations") {
Value *V = cast<Value>(I->getOperand(0));
errs()<<"\n "<<*(V)<<"\n";
errs()<<"\n "<<*(V->getType())<<"\n";
结果:
[1 x { i8*, i8*, i8*, i32 }] [{ i8*, i8*, i8*, i32 } { i8* bitcast (i32* @f to i8*), i8* getelementptr inbounds ([3 x i8]* @.str, i32 0, i32 0), i8* getelementptr inbounds ([9 x i8]* @.str1, i32 0, i32 0), i32 18 }]
[1 x { i8*, i8*, i8*, i32 }]
2.
errs()<<"\n "<<(V->getValueID())<<"\n";
if(V->getValueID() == Value::ConstantArrayVal) {
ConstantArray *ca = (ConstantArray *)V;
errs()<<"\n "<<(ca[0])<<"\n"; }
结果:
[1 x { i8*, i8*, i8*, i32 }] [{ i8*, i8*, i8*, i32 } { i8* bitcast (i32* @f to i8*), i8* getelementptr inbounds ([3 x i8]* @.str, i32 0, i32 0), i8* getelementptr inbounds ([9 x i8]* @.str1, i32 0, i32 0), i32 18 }]
欢迎任何帮助!谢谢 !
答
我解决了它。 我将整个带注释的表达式转换为值*。然后,为了避免像getAsString()这样的丑陋事情,我检查V->getValueID() == Value::ConstantArrayVal
是否将它转换为ConstantArray
。因为它只包含数组[0],所以我投射array0> getOperand(0)到ConstantStruct
。因此,从ConstantStruct
你可以得到所有的四个操作数。现在要做的只是从每个字段获取@f,@str的名称。这由ConstantStruct->getOperand(0)->getOperand(0)
完成。
答
如果您这样做,请使用runOnModule()而不是runOnFunction()。或者,你可以拿模块。 llvm.global.annotations在函数之外定义。内部做类似:
for (Module::global_iterator I = F.global_begin(), E = F.global_end(); I != E; ++I) {
if (I->getName() == "llvm.global.annotations")
{
errs()<<"\nllvm.global.annotations\n";
//1. find out what global variable is by "parsing" the IR
//2. get through the module till you find a load @f
//3. you can add metadata to the load function and you can easily get the metadata from the normal pass
}
}
答
这是一个很晚的答案,但Google在这里引导我,我认为提供一个完整的LLVM传递发现自由文本注释会有所帮助。 此LLVM传递只会记录带有__attribute((annotate(“someFreeTextAnnotation”)))标记的函数。代码如下:
#include "llvm/Pass.h"
#include "llvm/IR/Function.h"
#include "llvm/Support/raw_ostream.h"
#include "llvm/IR/Module.h"
#include "llvm/IR/Constants.h"
#include <set>
using namespace llvm;
const char *AnnotationString = "someFreeTextAnnotation";
namespace {
struct Hello : public FunctionPass {
static char ID;
Hello() : FunctionPass(ID) {}
std::set<Function*> annotFuncs;
virtual bool doInitialization(Module &M)override{
getAnnotatedFunctions(&M);
return false;
}
bool shouldInstrumentFunc(Function &F){
return annotFuncs.find(&F)!=annotFuncs.end();
}
void getAnnotatedFunctions(Module *M){
for (Module::global_iterator I = M->global_begin(),
E = M->global_end();
I != E;
++I) {
if (I->getName() == "llvm.global.annotations") {
ConstantArray *CA = dyn_cast<ConstantArray>(I->getOperand(0));
for(auto OI = CA->op_begin(); OI != CA->op_end(); ++OI){
ConstantStruct *CS = dyn_cast<ConstantStruct>(OI->get());
Function *FUNC = dyn_cast<Function>(CS->getOperand(0)->getOperand(0));
GlobalVariable *AnnotationGL = dyn_cast<GlobalVariable>(CS->getOperand(1)->getOperand(0));
StringRef annotation = dyn_cast<ConstantDataArray>(AnnotationGL->getInitializer())->getAsCString();
if(annotation.compare(AnnotationString)==0){
annotFuncs.insert(FUNC);
//errs() << "Found annotated function " << FUNC->getName()<<"\n";
}
}
}
}
}
bool runOnFunction(Function &F) override {
if(shouldInstrumentFunc(F)==false)
return false;
errs() << "Instrumenting " << F.getName() << "\n";
return false;
}
}; // end of struct Hello
} // end of anonymous namespace
char Hello::ID = 0;
static RegisterPass<Hello> X("hello", "Discover annotation attribute",
false /* Only looks at CFG */,
false /* Analysis Pass */);
感谢您的回复。我试图按照你的路线,我更新了我的问题。 – Alex 2013-02-28 11:02:49
我更新了我的回答。我将在小问题解决后编辑它。 – Alex 2013-03-01 12:35:40