无法从MySQL查询中获得期望的结果
我想在PHP中使用输出在MySQL中编写查询,但它证明相当困难。无法从MySQL查询中获得期望的结果
我有3列的表(是的,我知道这个数据库布局是不是最好的,但我不能改变这一点,客户有使用此数据库与此完全相同的布局等软件)
Amount - Product - Package
2 - Apple - Fruitbasket1
1 - Pear - Fruitbasket1
5 - Grape - Fruitbasket1
2 - Apple - Fruitbasket2
1 - Pear - Fruitbasket2
9 - Banana - Fruitbasket2
到目前为止,我想出了这一点:
SELECT package
FROM `data`
WHERE package IN
(
SELECT package
FROM `data`
WHERE product = 'apple' AND amount = '2'
)
AND package IN
(
SELECT package
FROM `data`
WHERE product = 'pear' AND amount ='1'
)
AND package IN
(
SELECT package
FROM `data`
WHERE product = 'grape' AND amount = '5'
)
LIMIT 0,1
的问题是,当客户将填写“苹果”和“2”的形式,它会返回一个包含2个苹果的所有篮子。我需要的是一份声明,它只接受确切的产品和金额,以返还那些成分所属的篮子,或者根本没有。
即使1个梨和2个苹果在Fruitbasket1中,但如果其他部分(即5个葡萄)未被客户指定,它也不应该给Fruitbasket1。
此查询将返回所有的包,唯一的产品是2个苹果
select package from `data`
group by package
having count(case when amount = 2 and product = 'Apple' then 1 end) = 1
and count(*) = 1
如果你想梨1个和2个苹果例如
select package from `data`
group by package
having count(
case
when (amount = 2 and product = 'Apple') or (amount = 1 and product = 'Pear')
then 1
end) = 2
and count(*) = 2
,你也可以这样写
select package from `data`
group by package
having count(case when amount = 2 and product = 'Apple' then 1 end) = 1
and count(case when amount = 1 and product = 'Pear' then 1 end) = 1
and count(*) = 2
我只有Oracle方便,所以你可能需要调整一些语法,但后续g您的原始风格我已添加“不在”部分,以确保篮子只包含您正在寻找的水果。这里有一些插入几个例子:
create table data (amount integer, product varchar(12), package varchar(16));
insert into data values (2, 'Apple', 'Fruitbasket1');
insert into data values (1, 'Pear', 'Fruitbasket1');
insert into data values (5, 'Grape', 'Fruitbasket1');
insert into data values (2, 'Apple', 'Fruitbasket2');
insert into data values (1, 'Pear', 'Fruitbasket2');
insert into data values (9, 'Banana', 'Fruitbasket2');
insert into data values (2, 'Apple', 'Fruitbasket3');
insert into data values (2, 'Apple', 'Fruitbasket4');
insert into data values (1, 'Pear', 'Fruitbasket4');
SELECT package
FROM data
WHERE package IN
(
SELECT package
from data
WHERE product = 'Apple' AND amount = '2'
)
and package not in
(
SELECT package
from data
WHERE product <> 'Apple'
)
group by package
;
SELECT package
FROM data
WHERE package IN
(
SELECT package
from data
WHERE product = 'Apple' AND amount = '2'
)
AND package IN
(
SELECT package
FROM data
WHERE product = 'Pear' AND amount ='1'
)
and package not in
(
SELECT package
from data
WHERE product <> 'Apple' and product <> 'Pear'
)
group by package
;
我会给你一个去,但FuzzyTree提供了一个更简洁的线:) – 2014-09-23 15:01:10
是的,完全同意:) – jas 2014-09-23 15:05:10
这个声明不会产生任何结果,悲哀。 – 2014-09-23 14:38:52
@RudyvanSloten你可以创建一个重现问题的小提琴吗? – FuzzyTree 2014-09-23 14:42:30
+1。 @RudyvanSloten:给出样本数据,我们希望这个查询返回0行,因为没有'package'只有'2 Apple''和''1 Pear''。为了让这个查询返回一行,我们还需要添加:**或(amount = 5和product ='Grape')**,并将**'= 2 ** **改为* *'= 3' **使它与“Fruitbasket1”匹配。我相信FuzzyTree提供的查询符合规范。 – spencer7593 2014-09-23 14:46:42