Python3脚本没有产生预期的结果

Question

我已经做了一个Python脚本来测试Monty Hall Problem 我的问题是，代码似乎输出30％的胜利和60％的损失时，它应该做的相反。

from random import randint 
wins = 0 
losses = 0 
for i in range(1000): 
    correctDoor = randint(1, 3) 
    guessDoor = randint(1, 3) 
    while True: 
     newGuessDoor = randint(1, 3) 
     if newGuessDoor != guessDoor: 
      break 
     elif newGuessDoor == guessDoor: 
      pass 
    if newGuessDoor == correctDoor: 
     wins = wins+1 
    else: 
     losses = losses+1 
print('Wins = ' + str(wins) + '\nLosses = ' + str(losses) + '') 

我觉得我错过了明显的东西。 任何帮助将不胜感激。

Answer 1

这实际上并没有正确实施Monty Hall问题。当初始猜测不正确时，另一个不正确的门在被提供切换之前被揭示，因此它是确定性选项。当最初的猜测是正确的时候，其他错误的门随机显示。

在你的实现中，在初始猜测之后，你不会得到任何额外的信息 - 你只是随机选择第二扇门，这与第一扇门不一样。

这里是你如何执行正确的方法的例子：

In [168]: from random import randint, choice 
    ...: wins = 0 
    ...: losses = 0 
    ...: for i in range(1000): 
    ...:  correctDoor = randint(1, 3) 
    ...:  guessDoor = randint(1, 3) 
    ...:  if guessDoor != correctDoor: 
    ...:   newGuessDoor = correctDoor 
    ...:  else: 
    ...:   newGuessDoor = choice([i for i in [1,2,3] if i != guessDoor]) 
    ...:  if newGuessDoor == correctDoor: 
    ...:   wins = wins+1 
    ...:  else: 
    ...:   losses = losses+1 
    ...: print('Wins = ' + str(wins) + '\nLosses = ' + str(losses) + '') 
    ...: 
Wins = 653 
Losses = 347