这是我们合作伙伴分配的运行长度编码程序。

Question

我们正在尝试对Javadoc进行指导。到目前为止，我们有这一点，但感到困惑与指数放慢参数

* Read the next run (or single character) and return the index of the symbol following the run (or symbol read). 
    * Store the count and symbol for the run in the run parameter. 
    * @param line - the input line being processed 
    * @param index - the index of the first character in the next "run" (which might be just a single character) 
    * @param run - where to store the symbol and count for the Run 
    * @return the index of the symbol following the run just read 
    */ 
    static int getNext(String line, int index, Run run) { 
    line.charAt(index); //char first, something about a line 
    return ?.symbol;//Store values 
    run.count= ?.count; //the given number of that specific symbol or repetition 
    enter code here 
    run.symbol= ?.symbol; //whatever symbol you first see 
    // TO BE COMPLETED 

    return index+1;// just to make it advance so starter program doesn't loop infinitely 
    } 
} 

Answer 1

这不是实际的RLE压缩功能，而是一个辅助函数来计算正由主RLE处理当前字符的重复压缩功能。

什么，这似乎需要做的是这样的：

• 以字符字符串时的line指数index，并将其存储在运行对象的相应属性。
• 在索引index之后，对line中的字符进行迭代，直至遇到与您在开始时所用的字符不相同的字符。
• 将找到的重复数量存储在Run对象的相应属性中。
• 返回字符串中遇到不等字符的位置。