PHP foreach循环只输出mysql表中的最后一个值

问题描述:

我一直在为这个foreach循环努力奋斗了一段时间。我需要做的是从我的数据库表中获取总和值,进行一些计算,然后使用css将它们显示为条形图。但我的foreach循环只给了我表中的最后一个值。任何帮助将非常感激,这里是我的代码示例:PHP foreach循环只输出mysql表中的最后一个值

<?php 

    $total_query = "select sum(amount_recieved) from reciepts"; 
    $total_result = safe_query($total_query); 

    $total = mysql_fetch_row($total_result); 

    $query = "select category_id from customer_categories"; 
    $result = safe_query($query); 

    while($cat_id = mysql_fetch_assoc($result)){ 

     foreach ($cat_id as $cat) { 

      $sum_query = "select sum(amount_recieved) from reciepts where category =".$cat.""; 
      $sum_result = safe_query($sum_query); 

      $sum = mysql_fetch_array($sum_result); 

      $percentage = ($sum[0]/$total[0]) * 100; 

      echo " 
       <li title='".$cat.", NGN ".$sum[0].", ".$percentage."%' class='bar' style=' 
        position:absolute; 
        bottom:0; 
        left:1%; 
        float:left; 
        width:7%; 
        height:".$percentage."%; 
        margin-right:1%; 
        margin-left:1%; 
        background:#999;'> 
       </li>"; 

      } 
    } 

?> 
+2

while循环遍历行,foreach遍历列,是你想要发生什么? –

+1

'customer_categories'表中有多少类别? – ajmedway

+1

真的不应该发布此任何更多:http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php – CD001

你的问题是,你的定位可以由数据完全相同的地方进行检索各条:

 echo " 
      <li title='" . $cat . ", NGN " . $sum[0] . ", " . $percentage . "%' class='bar' style=' 
       position:absolute; 
       bottom:0; 
       left:1%; 
       float:left; 
       width:7%; 
       height:" . $percentage . "%; 
       margin-right:1%; 
       margin-left:1%; 
       background:#999;'> 
      </li>"; 

浮动到左边,绝对定位到他们将被覆盖。无需对这些li元素进行绝对定位,请尝试删除position:absolute;

+1

重要的是你@ajmedway。这解决了我的问题... – Immanuel

+0

@Immanuel我很高兴听到,请你点击我的答案upvote?谢谢! :) – ajmedway

试试这个; $ sum_query =“select sum(amount_recieved)from reciepts where category =”。$ cat ['category_id'];