同步方法块执行
问题描述:
我正在实现一个带有三个类的虚拟程序,以更直观地参考Future
的工作方式。我的问题是,有时程序将被锁定在同步方法,它不会继续。我找不到原因。有人能够发现为什么没有一个战士会打印“我赢了”的路线吗?当块同步方法块执行
我的电流输出:
Fighter1
Fighter1已进入同步方法
Fighter2
Fighter2已进入同步方法
的代码如下。
主要类:
import java.util.concurrent.Callable;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
public class TmpTest {
private static final ExecutorService executorService =
Executors.newFixedThreadPool(2);
public static void main(final String... args) {
final Fighter fighter1 = new Fighter("Fighter1");
final Fighter fighter2 = new Fighter("Fighter2");
final Future<String> submitFighter1 = executorService.submit(fighter1);
final Future<String> submitFighter2 = executorService.submit(fighter2);
while (!submitFighter1.isDone() || !submitFighter2.isDone()) {
if (submitFighter1.isDone()) {
System.out.println("Fighter 1 wins!");
submitFighter2.cancel(true);
executorService.shutdown();
} else if (submitFighter2.isDone()) {
submitFighter1.cancel(true);
System.out.println("Fighter 2 wins!");
executorService.shutdown();
}
}
}
}
战斗机类:
class Fighter implements Callable<String> {
private final String fighterName;
private final ClassWithSyncMethod classWithSyncMethod;
public Fighter(final String fighterName) {
this.fighterName = fighterName;
classWithSyncMethod = new ClassWithSyncMethod(fighterName);
}
@Override
public String call() throws Exception {
return classWithSyncMethod.syncMethod();
}
}
虚拟类synchronized方法:
class ClassWithSyncMethod {
private final String fighterName;
public ClassWithSyncMethod(final String fighterName) {
this.fighterName = fighterName;
}
public synchronized String syncMethod() {
System.out.println(fighterName + " has entered the sync method");
try {
Thread.sleep(1000);
} catch (final InterruptedException e) {
System.out.println("Exception trying to sleep the fighter " + fighterName + ";" + e);
}
return fighterName + " shouts: I won!";
}
}
答
这有什么好做同步。每个战斗机在不同的物体上同步,所以它们不会相互干扰。
您看不到“我赢了”这一行的原因要简单得多 - 您永远不会打印它。 ClassWithSyncMethod#syncMethod()
方法(由Fighter#call()
返回)不会打印任何内容,它只是返回一个值。如果你想打印它,你必须自己去打印。
例如为:
while (!submitFighter1.isDone() || !submitFighter2.isDone()) {
if (submitFighter1.isDone()) {
System.out.println("Fighter 1 wins!");
System.out.println(submitFighter1.get()); // Here!
submitFighter2.cancel(true);
executorService.shutdown();
} else if (submitFighter2.isDone()) {
submitFighter1.cancel(true);
System.out.println("Fighter 2 wins!");
System.out.println(submitFighter2.get()); // And here!
executorService.shutdown();
}
}
你是绝对正确的。我是个白痴。谢谢! – Tavo
右键点'每个战士在不同的物体上同步',为你+1 –