是否有可能在“while”循环中更改变量的值？

Question

我试图编写代码来解决一个问题：

生成之间1和9（包括1和9）的随机数。要求用户猜出这个数字，然后告诉他们他们是否猜测得太低，太高，或者是否正确。跟踪用户采取了多少猜测，并在游戏结束时打印出来。

，我写的代码是：

import sys 
import random 
x=random.randint(1,9) 

print('Hello there! Please enter a number between 1 and 9 including the extremes.') 

for i in range (10): 
    z=input() 
    if int(z)<x: 
     print('Too low. Please try again.') 

    elif int(z)>x: 
     print('Too high. Please try again.') 

    elif int(z)==x: 
     print('You guessed it right!') 

    if i==0: 
     print('It took you a single turn! Nice') 
    else: 
     print('it took you ' + str(i+1)+' turns.') 

    print('Do you want to play again? Yes or No?') 

    j=input() 
    if j.lower()=='yes': 
     print('Okay, Please enter a number between 1 and 9 including the extremes.') 
     pass 
    else: 
     sys.exit() 

这里是它看起来运行时，如：

Hello there! Please enter a number between 1 and 9 including the extremes. 
4 
Too high. Please try again. 
3 
Too high. Please try again. 
2 
You guessed it right! 
it took you 3 turns. 
Do you want to play again? Yes or No? 
yes 
Okay, Please enter a number between 1 and 9 including the extremes. 
6 
Too high. Please try again. 
4 
Too high. Please try again. 
2 
You guessed it right! 
it took you 6 turns. 
Do you want to play again? Yes or No? 

看到，代码给出了完美的效果首先执行for循环时。当我们尝试第二次运行这个“游戏”时，它会给出奇怪的结果，通过说yes当它问我们问题：Do you want to play again? Yes or No?。

是否有可能把i=0当Python到达4号最后一行与for循环从i=0再次启动，这样我没有得到怪异的结果？

或者还有其他更简单的方法删除此错误吗？

Answer 1

您可以使用while循环执行任务。你应该添加异常处理方法来获取输入。

import random 

cond = True 

while cond: 
    print('Hello there! Please enter a number between 1 and 9 including the extremes.') 
    x=random.randint(1,9) 
    for i in range (10): 
     z=int(input()) 
     if int(z)<x: 
      print('Too low. Please try again.') 

     elif int(z)>x: 
      print('Too high. Please try again.') 

     elif int(z)==x: 
      print('You guessed it right!') 
      import sys 
      if i==0: 
       print('It took you a single turn! Nice') 
      else: 
       print('it took you ' + str(i+1)+' turns.') 

      print('Do you want to play again? Yes or No?') 
      j=input() 
      if j.lower()=='yes': 
       break 
      else: 
       cond = False 
       sys.exit() 

Answer 2

整个代码嵌入在for循环中，计数器永远不会重置。如果要在for循环中重置i，则必须在for循环之外定义它，以便它具有全局范围。

Answer 3

首先，你只选择一次随机数，所以它总是相同的。其次，你的游戏应该在while循环中而不是for循环中（如果你想让玩家在猜中后重新启动）。

turns = 0 
while True: 
    secret_number = random.randint(1,9) 
    print('Please enter a number between 1 and 9 including the extremes.') 
    guess = input() 
    turns += 1 
    if int(guess) < secret_number: 
     print("Too low") 
    elif int(guess) > secret_number: 
     print("Too high") 
    else: 
     print("You guessed in {} turn(s)".format(turns)) 

您继续循环，如果用户想继续玩轮流分配= 0，或者你分手，如果他没有。

Answer 4

我会这样写，可能。

from itertools import count 
from random import randint 


def run_game(): 
    random_value = randint(1, 9) 
    print('Hello there! Please enter a number between 1 and 9 including the extremes.') 

    for i in count(): 
     guess_string = input() 

     try: 
      guess = int(guess_string) 
     except ValueError: 
      print("Invalid value given for guess: {}".format(guess_string)) 

     if guess < random_value: 
      print("Too low! Please try again.") 

     elif guess > random_value: 
      print("Too high! Please try again.") 

     else: 
      print('You guessed it right!') 

      if not i: 
       print('It took you a single turn! Nice') 
      else: 
       print('it took you {} turns.'.format(i + 1)) 

      print('Do you want to play again? Yes or No?') 

      response_string = input() 
      return response_string.lower() == 'yes' 


if __name__ == "__main__": 
    while run_game(): 
     pass 

但是，对于理解简单：

from itertools import count 
from random import randint 

if __name__ == "__main__": 
    playing = True 
    while playing: 
     random_value = randint(1, 9) 
     print('Hello there! Please enter a number between 1 and 9 including the extremes.') 

     for i in count(): 
      guess_string = input() 

      try: 
       guess = int(guess_string) 
      except ValueError: 
       print("Invalid value given for guess: {}".format(guess_string)) 

      if guess < random_value: 
       print("Too low! Please try again.") 

      elif guess > random_value: 
       print("Too high! Please try again.") 

      else: 
       print('You guessed it right!') 

       if not i: 
        print('It took you a single turn! Nice') 
       else: 
        print('it took you {} turns.'.format(i + 1)) 

       print('Do you want to play again? Yes or No?') 

       response_string = input() 
       if response_string.lower() != 'yes': 
        playing = False 
       break 

Answer 5

所有进口应该在文件的顶部。然后，放一段时间，让玩家在每场比赛后重新开始;这样，变量x在每场比赛之后也被重置。此外，第一个打印应该放在while和for循环之外，所以它只打印一次（最后一个if会在新游戏开始时打印一个新提示）。
你在这一点上的代码应该是这样的：

import random 
import sys 
print('Hello there! Please enter a number between 1 and 9 including the extremes.') 
while True: 
    x=random.randint(1,9) 
    for i in range (10): 
     z=input() 
     if int(z)<x: 
      print('Too low. Please try again.') 
     elif int(z)>x: 
      print('Too high. Please try again.') 
     elif int(z)==x: 
      print('You guessed it right!') 
      if i==0: 
       print('It took you a single turn! Nice') 
      else: 
       print('it took you ' + str(i+1)+' turns.') 
      print('Do you want to play again? Yes or No?') 
      j=input() 
      if j.lower()=='yes': 
       print('Okay, Please enter a number between 1 and 9 including the extremes.') 
      else: 
       sys.exit()