加入两个MySQL表,但附加条件?
问题描述:
我有两个表:加入两个MySQL表,但附加条件?
产品:
+-------------------------------------------------+
| id | name | category | price |
+-------------------------------------- ----------+
| 1 | item1 | 1 | 0.99 |
| 2 | item2 | 2 | 1.99 |
| 3 | item3 | 3 | 2.95 |
| 4 | item4 | 4 | 2.50 |
+-------------------------------------------------+
图片:
+--------------------------------------------------+
| id | file_name | p_id | priority |
+-------------------------------------- -----------+
| 1 | image1 | 1 | 0 |
| 2 | image2 | 1 | 1 |
| 3 | image3 | 2 | 2 |
| 4 | image4 | 3 | 2 |
| 5 | image5 | 3 | 3 |
| 11 | image6 | 3 | 5 |
| 16 | image7 | 4 | 1 |
| 19 | image8 | 4 | 7 |
+--------------------------------------------------+
我需要把所有的产品信息,以及图像的文件名的产品。请注意,产品可以有多个图像;我想要最低优先。另外,我只希望获得某个类别产品的结果。
所以,说我需要在类{1,2,3}产品信息,然后在查询运行后的结果应该返回:
+-----------------------------------------------------------------+
| id | name | category | price | file_name |
+-------------------------------------- ----------+---------------+
| 1 | item1 | 1 | 0.99 | image1 |
| 2 | item2 | 2 | 1.99 | image3 |
| 3 | item3 | 3 | 2.95 | image4 |
+-------------------------------------------------+---------------+
我曾尝试写了几个不同的连接语句,但他们都没有工作;这并不奇怪,因为在SQL方面,我是一个总新手。
任何帮助将不胜感激!
答
这就是答案:
select a.id, a.name, a.category, a.price, b.filename as file_name
from products a left join (
select i.p_id, i.filename from (select id, min(priority) as min_p
from images group by p_id) q
left join images i on q.id = i.id
) b on a.id = b.p_id
where a.category in (1, 2, 3);
说明:
首先,你需要得到一组,其中对于每个具有最低优先级的产品,从此查询中获得:
select id, min(priority) as min_p from images group by p_id;
结果将是:
+----+----------+
| id | lowest_p |
+----+----------+
| 1 | 0 |
| 2 | 2 |
| 3 | 2 |
| 4 | 1 |
+----+----------+
4 rows in set (0.00 sec)
下一步会得到一个外连接,在这种情况下,我会选择(任意根据我的偏好),左联接:
select i.p_id, i.filename from (select id, min(priority) as min_p
from images group by p_id) q left join images i on q.id = i.id;
此查询产生你想要什么简称:
+------+----------+
| p_id | filename |
+------+----------+
| 1 | image1 |
| 2 | image3 |
| 3 | image4 |
| 4 | image7 |
+------+----------+
4 rows in set (0.00 sec)
现在你只需要装饰这一点,再次使用左连接:
select a.id, a.name, a.category, a.price, b.filename as file_name
from products a left join (
select i.p_id, i.filename from (select id, min(priority) as min_p
from images group by p_id) q
left join images i on q.id = i.id
) b on a.id = b.p_id
where a.category in (1, 2, 3);
,你会得到你想要的东西:
+------+-------+----------+-------+-----------+
| id | name | category | price | file_name |
+------+-------+----------+-------+-----------+
| 1 | item1 | 1 | 0.99 | image1 |
| 2 | item2 | 2 | 1.99 | image3 |
| 3 | item3 | 3 | 2.95 | image4 |
+------+-------+----------+-------+-----------+
3 rows in set (0.00 sec)
你也可以把产品在左边的右边加入,这取决于你所期望的时候有没有图像产品可用。上面的查询将显示上面的视图,其中file_name字段为“null”。
另一方面,如果您将产品放在左侧连接的右侧,它将不会显示任何内容。
答
我将添加一步一步的教程,首先获取联合权利, 然后添加一些条件来过滤类别,最后,分组 和使用具有子选择的having子句。您需要在代码中使用最后选择的 。我也在一个mysql实例上测试了它,它工作。 如果您需要其他复杂的东西,我正在使用group。有一个例子是很好的。 语法ANSII SQL,就应该对所有数据库的工作不只是在mysql
-- get everything by joining
select p.*, i.file_name
from products p
join image i on (p.id = i.p_id)
/* get everything by joining
* + filter by category
*/
select p.*, i.file_name
from products p
join image i on (p.id = i.p_id)
where p.category in (1,2,3)
/* get everything by joining
* + filter by category
* + image is the one with the lowest priority
* note: selecting the priority is not necessary
* but it's good for demonstration purposes
*/
select p.*, i.file_name, i.priority
from products p
join image i on (p.id = i.p_id)
where p.category in (1,2,3)
group by p.id
having i.priority = (select min(priority) from image where p_id = p.id)
答
大厦sarwar026的答案...
SELECT p.id, name, priority, price, file_name
FROM Products p, Images i
WHERE p.id = i.p_id
AND i.priority = (SELECT MIN(priority) FROM Images ii WHERE ii.p_id = p.id)
AND p.category IN (1,2,3)
(与你的表的副本MySQL数据库上测试)