SQLite的获取只有最后一个记录不是所有的记录
问题描述:
我也总4条记录ecare表,其中2 records
状态发送= 1,和其他2条状态sent = 0
SQLite的获取只有最后一个记录不是所有的记录
RECORDS
1st Record : Track 1 [sent = 1]
2nd Record : Track 2 [sent = 1]
3rd Record : Track 3 [sent = 0]
4th Record : Track 4 [sent = 0]
但只得到最后记录(即 - 轨道4)不全2记录那些状态发送= 0
这里是SQLite的查询,其中我使用来从数据库
public synchronized List<String> getECareData() {
String sql = "SELECT p.sent,e.*, e.no _id from ecare e LEFT JOIN pweb p ON e.h_id=p.h_id WHERE p.sent = '0' GROUP BY e.h_id";
List<String> records = new ArrayList<String>();
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(sql, null);
while (cursor.moveToNext()) {
records.add(cursor.getString(0));
}
return records;
}
数据进行更新
public synchronized List<String> getECareData() {
String sql = "SELECT p.sent,e.*, e.no _id from ecare e LEFT JOIN pweb p ON e.h_id=p.h_id WHERE p.sent = '0' GROUP BY e.h_id";
List<String> records = new ArrayList<String>();
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(sql, null);
// looping through all rows and adding to list
if (cursor.moveToFirst()) {
do {
records.add(cursor.getString(0));
} while (cursor.moveToNext());
}
Log.d("records:", records.toString());
return records;
}
日志说:
D/records:: [Getting only LAST record here] the 4th one
我想,有一个与查询东西wrong
,因为我在只获得最后一个记录光标
更新的记录
1st Record : Track 1 [sent = 1]
2nd Record : Track 2 [sent = 1]
3rd Record : Track 3 [sent = 0]
4th Record : Track 4 [sent = 0]
5th Record : Track 5 [sent = 0]
但只得到最后记录(即 - 轨道5)不所有三个记录那些状态发送= 0
日志说:
D/records:: [Getting only LAST record here] the 5th one
更新的查询 - 从查询中移除GROUP BY
现在得到每一条记录,即使是那些属于的发送= 1而我只是想获取属于发送= 0的数据仅
String sql = "SELECT p.sent,e.*, e.no _id from ecare e LEFT JOIN pweb p ON e.h_id=p.h_id WHERE p.sent = '0' ";
答
你缺少startManagingCursor()
方法。
Cursor cursor = db.rawQuery(sql, null);
cursor.getCount();
startManagingCursor(cursor);//the important line
cursor.moveToFirst();
if(cursor.getCount() == 0)
{
//error no records
}
else
{
for(int i=0;i<cursor.getCount();i++)
{
records.add(cursor.getString(0));
adapter.add(aString);
cursor.moveToNext();
}
cursor.moveToFirst();
}
注: startManagingCursor()
被推荐使用,因为它的主线程可以冻结用户界面,并提供一个不好的用户体验上的操作。您应该使用CursorLoader
而不是LoaderManager
。
答
我会尝试:
String sql = "SELECT p.sent,e.*, e.no _id
FROM ecare e, pweb p
WHERE e.h_id=p.h_id
AND e.sent = '0' ";
答
我试图重新创建数据库,这是正确的,这是什么问题,似乎工作。
CREATE TABLE ecare (_id INTEGER PRIMARY KEY,h_id INTEGER ,no INTEGER);
CREATE TABLE pweb (_id INTEGER PRIMARY KEY,h_id INTEGER ,sent INTEGER);
sqlite> insert into ecare values(1, 10,1);
sqlite> insert into ecare values(2, 20,2);
sqlite> insert into ecare values(3, 30,3);
sqlite> insert into ecare values(4, 40,4);
sqlite>
sqlite> insert into pweb values(1, 10,1);
sqlite> insert into pweb values(2, 20,1);
sqlite> insert into pweb values(3, 30,0);
sqlite> insert into pweb values(4, 40,0);
sqlite> select * from ecare;
1|10|1
2|20|2
3|30|3
4|40|4
sqlite> select * from pweb;
1|10|1
2|20|1
3|30|0
4|40|0
sqlite> SELECT p.sent,e.*, e.no _id from ecare e LEFT JOIN pweb p ON e.h_id=p.h_id WHERE p.sent = '0';
0|3|30|3|3
0|4|40|4|4
sqlite>
在while循环之前执行cursor.moveToFirst()。 –
请注意,'LEFT JOIN p ... WHERE p ...'与'INNER JOIN p'相同' – Strawberry
@ayeshdon请参阅UPDATED部分,但仍只获得最后一条记录,不是记录 – Oreo