以递归方式压缩包含任意数量的Java文件和子目录的目录？

Question

是否有递归压缩ZIP目录的简单方法，该目录可能包含或不包含任何数量的文件和任意数目的子目录级别？

Answer 1

您可以使用： http://java.sun.com/j2se/1.4.2/docs/api/ 和： http://www.java-forums.org/new-java/4123-how-do-you-recursively-traverse-through-file-folders.html

Answer 2

我在ruby中使用ZipFileSystem实现取得了巨大成功，尽管我从未在java中使用它。你可能想看看this出：

Answer 3

public final class ZipFileUtil { 
    public static void zipDirectory(File dir, File zipFile) throws IOException { 
     FileOutputStream fout = new FileOutputStream(zipFile); 
     ZipOutputStream zout = new ZipOutputStream(fout); 
     zipSubDirectory("", dir, zout); 
     zout.close(); 
    } 

    private static void zipSubDirectory(String basePath, File dir, ZipOutputStream zout) throws IOException { 
     byte[] buffer = new byte[4096]; 
     File[] files = dir.listFiles(); 
     for (File file : files) { 
      if (file.isDirectory()) { 
       String path = basePath + file.getName() + "/"; 
       zout.putNextEntry(new ZipEntry(path)); 
       zipSubDirectory(path, file, zout); 
       zout.closeEntry(); 
      } else { 
       FileInputStream fin = new FileInputStream(file); 
       zout.putNextEntry(new ZipEntry(basePath + file.getName())); 
       int length; 
       while ((length = fin.read(buffer)) > 0) { 
        zout.write(buffer, 0, length); 
       } 
       zout.closeEntry(); 
       fin.close(); 
      } 
     } 
    } 
}