PHP-SQL的非法参数编号：绑定变量的数量不符令牌

Question

此代码giveing我这个错误的号码：非法参数编号：绑定变量的数量不匹配的令牌数量

$fields[':email']=$_GET["email"]; 
$fields[':password']=$_GET["password"]; 
$fields[':telefono']=$_GET["telefono"]; 
$fields[':old_email']=$_GET["old_email"]; 
$fields[':isAdmin']=0; 
$qry.="UPDATE utente SET Email:=email, Password:=password ,Telefono:=telefono, isAdmin=:isAdmin WHERE Email=:old_email"; 
$sth=$CONNESSIONE->prepare($qry); 
$sth->execute($fields); 

（5）{[“：email”] => string（5）“test2”[“：password”] => string（1）“b”[“：telefono” ] => string（7）“0415600”[“：old_email”] => string（4）“test”[“：isAdmin”] => int（0）}

and my table is this

CREATE TABLE IF NOT EXISTS `utente` (
    `Email` varchar(150) COLLATE utf8_unicode_ci NOT NULL, 
    `Password` varchar(150) COLLATE utf8_unicode_ci NOT NULL, 
    `Telefono` varchar(150) COLLATE utf8_unicode_ci NOT NULL, 
    `isAdmin` tinyint(1) NOT NULL, 
    UNIQUE KEY `Email` (`Email`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; 

为什么这不起作用？

Answer 1

改变这种

$qry.="Email:=email, Password:=password ,Telefono:=telefono, isAdmin=:isAdmin WHERE Email=:old_email"; 

到

$qry.="Email=:email, Password=:password ,Telefono=:telefono, isAdmin=:isAdmin WHERE Email=:old_email"; 

您=