MySQL中INSERT INTO ... ON DUPLICATE KEY UPDATE的正确语法是什么？

Question

我的表（S）结构（的MySQL /每个人都是下同）

+-------+--------------+------+------+-------------------+ 
| Field | Type   | Null | Key | Default   | 
+-------+--------------+------+------+-------------------+ 
| id | int(11)  | NO | PRI | AUTO INCREMENT | 
| lesson| varchar(255) | NO |  | LESSON_NAME  | 
| exam | char(50)  | NO |UNIQUE| NO DEFAULT  | 
| quest | text   | NO |  | NO DEFAULT  | 
| answer| text   | NO |  | NO DEFAULT  | 
| note | text   | NO |  | NO DEFAULT  | 
+-------+--------------+------+------+-------------------+ 

和我'张贴一些值通过AJAX（$ POST）来加入这个表 - PHP 5.0
在database.php中有一个函数来获取发布的数据，并添加到表

function update_table ($proper_table, $name, $question, $answer, $note) { 
$sql = "INSERT INTO $proper_table (id, lesson, exam, quest, answer, note) VALUES ('', '', $name, $question,$answer,$note) ON DUPLICATE KEY UPDATE exam = $name, quest = $question, answer = $answer, note = $note"; 
$result= mysql_query($sql)or die(mysql_error()); 
} 

$ proper_table变量采取的是另一个变量添加这个记录更正表。
（注意：原始表格字段和变量不同（土耳其语），我可以更容易理解，但是其语法与您看到的相同。）
问题：我想检查是否有记录考试领域是相同的，那么所有这些变量将用于更新此记录，否则让函数将此记录作为新记录放在适当的表中。
但是像下面

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 

我'得到错误有任何编码错误？什么是解决方案？
由于现在...

Answer 1

function update_table ($proper_table, $name, $question, $answer, $note) { 
    $sql = "INSERT INTO $proper_table (lesson, exam, quest, answer, note) VALUES ('', '$name', '$question','$answer','$note') ON DUPLICATE KEY UPDATE quest = VALUES(quest), answer = VALUES(answer), note = VALUES(note)"; 
    $result= mysql_query($sql)or die(mysql_error()); 
} 

刚刚突破了这一点，我会详细的变化

$sql = "INSERT INTO $proper_table 

// Removed the PK AI field - don't need to specify this 
(lesson, exam, quest, answer, note)  

// Likewise removed PK field, and added quotes around the text fields 
VALUES ('', '$name', '$question','$answer','$note')  
ON DUPLICATE KEY UPDATE 

// If you specify VALUES(fieldName) it will update with the value you specified for the field in the conflicting row 
// Also removed the exam update, as exam is the UNIQUE key which could cause conflicts so updating that would have no effect 
quest = VALUES(quest), answer = VALUES(answer), note = VALUES(note)"; 

Answer 2

你需要用单引号括起来，你字符串变量在SQL '$name'例如。否则，mysql认为你在引用列名。

Answer 3

使用该查询，当您添加ON DUPLICATE KEY UPDATE时，它将在id与发送的id相同时更新，在这种情况下，您没有发送id作为参数，所以它不会更新，因为你有自动增量的ID。

一个解决方案可能是，你读这里的考试等于您发送的参数表中，这样的事情：

SELECT id FROM $proper_table; 

如果是空的执行插入，如果它不是空的你以参数更新为参数您从选择中获得的ID

Answer 4

id自动增量，所以想必您不想将空字符串设置为id。

尝试：

$sql = "INSERT INTO $proper_table (lesson, exam, quest, answer, note) VALUES ('', $name, $question,$answer,$note) ON DUPLICATE KEY UPDATE exam = $name, quest = $question, answer = $answer, note = $note"; 

Answer 5

你必须要像这样

<?php 
function update_table($proper_table, $name, $question, $answer, $note, $id) { 

    $sqlQuery = "INSERT INTO '".$proper_table."' SET 
        name  =  '".$name."', 
        question  = '".$question."', 
        answer  =  '".$answer."', 
        note  =  '".$note."' WHERE id = '".$id."'"; 

    $result= mysql_query($sqlQuery)or die(mysql_error()); 

} 
?>