在PHP中替代变量变量
问题描述:
在此循环中,我遍历数组并每次执行一次API调用。这工作正常,但我一直在阅读,使用变量变量是不好的做法。我如何重写这段代码而不使用它们?在PHP中替代变量变量
编辑:我没有使用数组,因为我必须将变量传递到另一个模板中,并在该数组之外具有其他变量。
template('template-name', [ 'graphOne' => $graphOne, 'graphTwo' => $graphTwo, 'outsideVar' => $anothervalue ]);
<?php
// Array of categories for each graph
$catArray = [
'One' => '3791741',
'Two' => '3791748',
'Three' => '3791742',
'Four' => '3791748'
];
foreach ($catArray as $graphNum => $cat)
{
// Hit API
$graph_results = theme('bwatch_graph_call', [
'project' => '153821205',
'category' => $cat
]
);
${"graph{$graphNum}"} = $graph_results;
// Outputs $graphOne, $graphTwo, $graphThree...
}
// Pass vars to template
template('template-name', [
'graphOne' => $graphOne,
'graphTwo' => $graphTwo,
'outsideVar' => $anothervalue ]
);
答
您可以使用PHP的array_merge
当你让你的template()
电话,如果你有不同的密钥多个阵列=>值对。
下面是一个例子,如果你有多个阵列(密钥=>值对)要传递到模板中。
// Array of categories for each graph
$catArray = [
'One' => '3791741',
'Two' => '3791748',
'Three' => '3791742',
'Four' => '3791748'
];
// Array of category results
$catResult = [];
foreach ($catArray as $graphNum => $cat)
{
// Hit API
$catResult['graph' . $graphNum] = theme('bwatch_graph_call', [
'project' => '153821205',
'category' => $cat
]
);
}
// Now you have an array of results like...
// $catResult['graphOne'] = 'result for One';
// $catResult['graphTwo'] = 'result for Two';
$otherArray1 = ['outsideVar' => $anothervalue];
$otherArray2 = ['somethingElse' => $oneMoreValue];
// Pass all arrays as one
template('template-name', array_merge($catResult, $otherArray1, $otherArray2));
+0
非常感谢,很有道理。 – user3869231
使用另一个阵列,以保持结果:'$图[$ graphNum] = $ graph_results;' – axiac
你可以有一个数组?像'$ graphs = [];'在'foreach'之前,然后分配'$ graphs [$ graphNum] = $ graph_results;' – Giedrius
不使用数组的任何特定原因?如果你真的需要这些变量,你可能想看看这个http://php.net/manual/en/function.extract.php – Nima