如何将此日期格式与正则表达式匹配？

Question

嗨，所有正则表达式大师在那里，我知道你有一个解决我的问题。和合

02-May-2011 

或

22-May-2011 

或

2-May-2011 

（DD-MMM-YYYY） 用YYYY不接受任何其他字符不是数字

Answer 1

[0-9]{1,2}/[a-zA-Z]{3}/[0-9]{4} 

这是假设那个月是一个3个字母的版本：例如，一月，二月，三月

版本更新相匹配的更改问题：

[0-9]{1,2}-[a-zA-Z]{3}-[0-9]{4} 

正如已经提到的，这不会实际验证的日期，它将只验证字符串匹配的格式为：1或2个数字，短划线，3个字母，短划线，4个数字。

Answer 2

^\d{1,2}/[a-zA-Z]+/\d{4}$ 

可能是你在找什么。虽然技术上是正确的一句是：

/^([12]\d|3[01])/(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)/\d{4}$/i 

对不起，不验证2月和一个月的天数，但也有不值得做的正则表达式中的一些东西;）

Answer 3

使用的SimpleDateFormat代替使用正则表达式。请参阅http://download.oracle.com/javase/tutorial/i18n/format/simpleDateFormat.html以获取更多信息。

Answer 4

/** 
    * Created with IntelliJ IDEA. 
    * User: S34N 
    * Date: 2013/07/30 
    * Time: 8:21 AM 
    * To change this template use File | Settings | File Templates. 
    */ 



    //Import the required classes/packages 
    import javax.swing.*; 
    import java.text.DateFormat; 
    import java.text.SimpleDateFormat; 
    import java.util.Date; 

    public class dateInputScan { 

     public static void main(String args[]) { 

      dateInputScan run = new dateInputScan(); 
      run.dateInputScan(); 
     } 

     public void dateInputScan() { 

      //Instantiating variables 
      String lvarStrDateOfTransaction = null; 
      DateFormat formatter = null; 
      Date lvarObjDateOfTransaction = null; 

      //Use one of the following date formats. 
      lvarStrDateOfTransaction = "29/07/2013"; 
      //lvarStrDateOfTransaction = "29-07-2013"; 
      //lvarStrDateOfTransaction = "20130729"; 
      //lvarStrDateOfTransaction = "2013-07-29"; 
      //lvarStrDateOfTransaction = "29/07/2013"; 

      //You can also add your own regex (Regular Expression) 
      if (lvarStrDateOfTransaction.matches("([0-9]{2})/([0-9]{2})/([0-9]{4})")) { 
       formatter = new SimpleDateFormat("dd/MM/yyyy"); 
      } else if (lvarStrDateOfTransaction.matches("([0-9]{2})-([0-9]{2})-([0-9]{4})")) { 
       formatter = new SimpleDateFormat("dd-MM-yyyy"); 
      } else if (lvarStrDateOfTransaction.matches("([0-9]{4})([0-9]{2})([0-9]{2})")) { 
       formatter = new SimpleDateFormat("yyyyMMdd"); 
      } else if (lvarStrDateOfTransaction.matches("([0-9]{4})-([0-9]{2})-([0-9]{2})")) { 
       formatter = new SimpleDateFormat("yyyy-MM-dd"); 
      } else if (lvarStrDateOfTransaction.matches("([0-9]{4})/([0-9]{2})/([0-9]{2})")) { 
       formatter = new SimpleDateFormat("yyyy/MM/dd"); 
      } 

      try { 
       lvarObjDateOfTransaction = formatter.parse(lvarStrDateOfTransaction); 
       JOptionPane.showMessageDialog(null, "Date: " + lvarObjDateOfTransaction); 

      } catch (Exception ex) { //Catch the Exception in case the format is not found. 
       JOptionPane.showMessageDialog(null, ex); 
      } 
     } 
    } 

Answer 5

好的，这是日期模式的几乎所有可能的正则表达式的变化： “”

private final static Pattern DATE_PATTERN_1 = 

     Pattern.compile (
      "(?:Sun|Mon|Tue|Wed|Thu|Fri|Sat) " + 
      "(?:Jan|Feb|Mar|Apr|May|June?|July?|Aug|Sept?|Oct|Nov|Dec) " + 
      "\\d\\d \\d\\d:\\d\\d:\\d\\d \\S+ \\d\\d\\d\\d", Pattern.CASE_INSENSITIVE); 

private final static Pattern DATE_PATTERN_2 = 
     Pattern.compile (
      "\\d{4}.\\d{2}.\\d{2}", Pattern.CASE_INSENSITIVE); 

private final static Pattern DATE_PATTERN_3 = 
     Pattern.compile (
      "\\d{2}.\\d{2}.\\d{4}", Pattern.CASE_INSENSITIVE); 

private final static Pattern DATE_PATTERN_4 = 
     Pattern.compile (
      "([0-9]{4})([0-9]{2})([0-9]{2})", Pattern.CASE_INSENSITIVE);   

private final static Pattern DATE_PATTERN_5 = 
     Pattern.compile (
      "^([12]\\d|3[01]).(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|June?|July?|Aug(ust)?|Sep(t(ember)?)?|Oct(ober)?|Nov(ember)?|Dec(ember)?).\\d{4})$", Pattern.CASE_INSENSITIVE); 

请注意，字符代表任何字符。