类型错误：做不是一个函数护照

Question

passport.use('local.signup', new Localstrategy({ 
    usernameField: 'email', 
    passwordField: 'password', 
    roleField: 'role', 
    passReqToCallback: true 
}, function(req, email, password, role, done) { 
    req.checkBody('email', 'Invalid Email').notEmpty().isEmail(); 
    req.checkBody('password', 'Invalid Password ').notEmpty().isLength({min:4}); 
    req.checkBody('role', 'Invalid Password').notEmpty(); 
    var errors = req.validationErrors(); 
    if (errors) { 
     var messages = []; 
     errors.forEach(function(error) { 
      messages.push(error.msg); 
     }); 
     return done(null, false, req.flash('error', messages)); 
    } 
    // what the... 
    User.findOne({ 
     'email': email 
    }, function(err, user) { 
     if (err) { 
      return done(err); 
     } 
     if (user) { 
      return done(null, false, { 
       message: 'Email is already in use.' 
      }); 
     } 
     var newUser = new User(); 
     newUser.email = email; 
     newUser.password = newUser.encryptPassword(password); 
     newUser.role = role; 
     newUser.save(function(err, result) { 
      if (err) { 
       return done(err); 
      } 
      return done(null, newUser); 
     }); 
    }); 
})); 

Answer 1

我不相信这个设置会做任何事：

function(req, email, password, role, done) { 

：

roleField: 'role', 

您可以通过这个改变你的函数的参数修复错误

对此：

function(req, email, password, done) {