Marklogic - 在Java api中插入pojo作为json文档

Question

我想在使用java api的marklogic中插入pojo对象作为json文档。我使用this作为插入pojo作为xml文档的参考。

我无法注册我的pojo类与JSON句柄。

public class JSONDocument { 
    public static void main(String[] args) throws JAXBException, IOException { 
     run(Util.loadProperties()); 
    } 
    @JsonRootName(value = "product") 
    static public class Product { 
     @JsonProperty 
     private String name; 
     @JsonProperty 
     private String industry; 
     @JsonProperty 
     private String description; 
     public Product() { 
      super(); 
     } 
     public String getName() { 
      return name; 
     } 
     public void setName(String name) { 
      this.name = name; 
     } 
     public String getIndustry() { 
      return industry; 
     } 
     public void setIndustry(String industry) { 
      this.industry = industry; 
     } 
     public String getDescription() { 
      return description; 
     } 
     public void setDescription(String description) { 
      this.description = description; 
     } 
    } 

    public static void run(ExampleProperties props) throws JAXBException { 

     runShortcut(props); 

     System.out.println("Wrote, read, and deleted "+Product.class.getName()+" using JAXB"); 
    } 
    public static void runShortcut(ExampleProperties props) throws JAXBException { 
     // register the POJO classes like JAXB - JAXBHandle.newFactory(Product.class) 

     DatabaseClientFactory.getHandleRegistry().register(
      // Need help here for - registering pojo for JSON 

     ); 
     // create the client 
     DatabaseClient client = DatabaseClientFactory.newClient(
       props.host, props.port, props.writerUser, props.writerPassword, 
       props.authType); 

     // create a manager for JSON documents 
     JSONDocumentManager docMgr = client.newJSONDocumentManager(); 

     // create an instance of the POJO class 
     Product product = new Product(); 
     product.setName("FashionForward"); 
     product.setIndustry("Retail"); 
     product.setDescription(
       "(Shortcut) Creates demand with high prices, hours from midnight to dawn, and frequent moves"); 

     // create an identifier for the document 
     String docId = "/example/"+product.getName()+".json"; 

     // write the POJO as the document content 
     docMgr.writeAs(docId, product); 

     // ... at some other time ... 

     // read the POJO from the document content 
     product = docMgr.readAs(docId, Product.class); 

     // log the persisted Json document 
     System.out.println(docMgr.readAs(docId, String.class)); 


     // release the client 
     client.release(); 
    } 
} 

如果我在这个例子中错了，请让我知道正确的方式，并帮助我解决这个问题。

感谢您的阅读。

Answer 1

尽管您可以使用JAXB将您的pojo序列化为JSON，但许多人更喜欢Jackson和我们的JacksonDatabindHandle。请参阅example in JacksonDatabindTest并注意the City class is registered on lines 68-69。或者，如果您不需要控制数据库中JSON的外观，最简单的方法是使用POJO Data Binding Interface。