脚本终止时释放Python Flask端口

Question

我有一个使用HTTPS的Python Flask服务器。当我按CTRL-C终止时，列表程序仍在运行（我必须在shell中运行：sudo fuser 8080/tcp -k来终止它）。我想要一个更好的方式来释放它。任何人都知道使用正确的Flask代码？

import sys 
import os 
import signal 
from flask import Flask, render_template, url_for, current_app, request 
from OpenSSL import SSL 

# Clean-up when press CTRL+C 
def signal_handler(signal, frame): 
     # I want to release the port here 
     print('Clean-up') 
     sys.exit(0) 
signal.signal(signal.SIGINT, signal_handler) 

context = SSL.Context(SSL.SSLv23_METHOD) 
context.use_privatekey_file('server.key') 
context.use_certificate_file('server.crt') 

app = Flask(__name__) 

@app.route("/<arg1>") 
def route1(arg1): 
    return render_template("flask_page1.html", var1=arg1) 

app.run(host="0.0.0.0", port=8080, debug=False, ssl_context=context) 

的Python 2.7，树莓派运行Raspbian

Answer 1

我正是曾与瓶同样的问题，我终于结束了猴子修补socket模块本身。添加后，您的进口：

# patch socket module 
socket.socket._bind = socket.socket.bind 
def my_socket_bind(self, *args, **kwargs): 
    self.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) 
    return socket.socket._bind(self, *args, **kwargs) 
socket.socket.bind = my_socket_bind 

我没有找到任何其他方式。