无法从异步方法完成回调更新Silverlight UI
问题描述:
我继承了一些通过WCF服务查询数据库的代码,然后在完成时使用回调。我正在尝试向该回调中添加一些代码,以便在数据处理时更新UI。我发现,我不能让UI到回调过程中更新:直到(显然)整个回调完成无法从异步方法完成回调更新Silverlight UI
client.GetDataAsync();
client.GetDataCompleted += new EventHandler<GetDataCompletedEventArgs>(GetDataCompleted);
void GetDataCompleted(object sender, GetDataCompletedEventArgs e)
{
// Loop through the data
// ...
textBlock1.Text= "test1";
Dispatcher.BeginInvoke(() => textBlock1.Text= "test2");
var thread = new Thread(() =>
{
// textBlock1.Text= "test3"; (this throws a cross-thread access exception)
Dispatcher.BeginInvoke(() =>
{
textBlock1.Text= "test4";
});
}
thread.Start();
// ...
Debug.WriteLine("done");
}
这一切都不更新UI。这个帖子:
What thread calls the completed event handler on silverlight WCF calls?
表明回调的主UI线程上运行,这样的BeginInvoke的调用应该是不必要的。即使我在上面的代码中添加了各种延迟,它仍然不起作用。这可能吗?有一个更好的方法吗?
(这是一个后续问题是:Multiple asynchronous UI updates in Silverlight)
答
degorolls是正确的暗示TPL,你的代码看起来像下面的(除了没有评论)(另外,异常必须在办理TPL,所以这可能使它不值得,但我不认为它应该)。 第一种方法将保持不变,并且是在基于事件的异步编程中,线程安全性得到了处理(即:您总是返回到您调出的同一线程) 我还注意到文本输出全部正在执行=而不是+ =,但这可能更像是输入溢出问题 因此,test1和test2会同时打印出来,但是从TPL代码中吐出的所有东西都应该打印出来。 UI代码不应该做任何需要太多时间的事情,尽管......只更新UI。那么,请将此视为重构的一点吗? 让我知道这是否有帮助,或者如果我错过了你要找的东西。
client.GetDataAsync();
client.GetDataCompleted += new EventHandler<GetDataCompletedEventArgs>(GetDataCompleted);
void GetDataCompleted(object sender, GetDataCompletedEventArgs e)
{
// Loop through the data
// ...
textBlock1.Text= "test1";
//////Dispatcher should not be needed here as this IS on the main UI thread
Dispatcher.BeginInvoke(() => textBlock1.Text= "test2");
//////Everything that happens here should NOT be on the main UI thread, thus the cross-thread access exception
//////You can do Dispatcher.CheckAccess to determine if you need to invoke or not
//////Notice the newCopyOfDataToBeWritten. This is a closure,
//////so using the same referenced object will result in errant data as it loops
//////Also, doing it this way does not guarantee any order that this will be written out
//////This will utilize the parallel fully, but there are ways to force the order
var task = Task.Factory.StartNew(()=>
{
Dispatcher.BeginInvoke(()=>textBlock1.Text += newCopyOfDataToBeWritten)
}
);
// ...
///////I assume this is the end of the loop?
Debug.WriteLine("done");
}
.... 以下空置向下代码根据你发布什么似乎为我
var outsideThread = new Thread(()=>
{
for(int i = 0; i < 20; i++)
{
//This code will show all at once since it is on the main thread,
//which is still running
//If you want this to display one at a time also, then you need
//to use threads and callbacks like below, also
Dispatcher.BeginInvoke(()=>{textBlock1.Text += "outer" + i;});
int newI = i;
var thread = new Thread(() =>
{
System.Threading.Thread.Sleep(1000 * newI);
Dispatcher.BeginInvoke(() =>
{
//This will display as it comes in
textBlock1.Text += "inner" + newI;
});
});
thread.Start();
}
});
outsideThread.Start();
工作(是吗?一个更好的方法)的Silverlight您正在使用什么版本?新的Task.Factory.FromAsync工程是一种享受。您摆脱了事件处理程序,代码变得更加可读,并且您可以更好地控制事件执行的地点/时间。 – 2012-02-17 04:44:24