用户输入访问元素数组

Question

我是新来的Java，我想让用户可以从他们要求的数组中获得什么元素。

int[] aksesArray = {30, 50, 10, 90, 70}; 

因此，如果用户输入一个答案0，他将获得访问元素0这是30，等等。并且，无论何时用户输入0, 1, 2, 3, 4答案将始终引用30.

我认为问题是在我的a = aksesArray.length;

import javax.swing.JOptionPane; 

public class pickingArray { 


public static void main(String[] args) { 

int[] aksesArray = {30, 50, 10, 90, 70}; 

int inputElm = Integer.parseInt(JOptionPane.showInputDialog("Input Number to find an Element ")); 
int a = (inputElm); 

a = aksesArray.length; 


    if (a == aksesArray.length) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[0]); 
    } 
    else if (a == aksesArray[1]) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[1]); 
    } 
    else if (a == aksesArray.length) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[2]); 
    } 
    else if (a == aksesArray.length) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[3]); 
    } 
    else if (a == aksesArray.length) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[4]); 
    } 
    else { 
     JOptionPane.showMessageDialog(null, "No Element "); 
    } 


    } 

} 

Answer 1

可以大大检查，如果输入的数字是aksesArray的范围内，简化代码。无论哪种情况，您都可以打印适当的消息。

public static void main(String[] args) { 
    int[] aksesArray = {30, 50, 10, 90, 70}; 

    int inputElm = Integer.parseInt(JOptionPane.showInputDialog("Input Number to find an Element ")); 

    if (inputElm >= 0 && inputElm < aksesArray.length) { 
     JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[inputElm]); 
    } 
    else { 
     JOptionPane.showMessageDialog(null, "No Element "); 
    } 
}