在Angular 2/4中显示特定数据

在Angular 2/4中显示特定数据

问题描述:

我有一个包含material_projects或project_services的项目api。我很困惑我将如何显示其中一个。如果我显示material_projects,那么我不能显示project_services。 project_services在api中必须是空的。在Angular 2/4中显示特定数据

getAllProjects() { 
    this.subscription = this.projectsService.getAll() 
     .subscribe(
     (data:any) => { 
      this.projects = data.projects; 
      console.log(data); 
     }, 
     error => { 
      console.log(error); 
     }); 
    } 

HTML

<div class="card-block" *ngFor="let project of projects | search : searchBOM"> 
    <h2 class="proj-name">{{ project.name | titlecase }} </h2> 
    <table class="table table-bordered table-striped"> 
    <thead> 
     <tr> 
     <th>Material SKU</th> 
     <th>Material Name</th> 
     <th>Unit</th> 
     </tr> 
    </thead> 
    <tbody> 
     <tr *ngFor="let innerItem of project.material_projects"> 
     <td>{{innerItem.material.sku}}</td> 
     <td>{{innerItem.material.name}}</td> 
     <td>{{innerItem.unit}}</td> 
     </tr> 
    </tbody> 
    </table> 
</div> 

enter image description here

如果你能保证约束,那么你可以简单地在两个列表进行迭代。

<tbody> 
    <tr *ngFor="let innerItem of project.material_projects"> 
    <td>{{innerItem.material.sku}}</td> 
    <td>{{innerItem.material.name}}</td> 
    <td>{{innerItem.unit}}</td> 
    </tr> 
    <tr *ngFor="let innerItem of project.project_services"> 
    <td>{{innerItem.service.sku}}</td> 
    <td>{{innerItem.service.name}}</td> 
    <td>{{innerItem.unit}}</td> 
    </tr> 
</tbody> 

作为替代方案,可以有条件地显示的一个或另一个:

<tbody> 
    <ng-container *ngIf="project.material_projects.length > 0; then #materialProjectsRows; else #projectServicesRows"></ng-container> 
    <ng-template #materialProjectsRows> 
    <tr *ngFor="let innerItem of project.material_projects"> 
     <td>{{innerItem.material.sku}}</td> 
     <td>{{innerItem.material.name}}</td> 
     <td>{{innerItem.unit}}</td> 
    </tr> 
    </ng-template> 
    <ng-template #projectServicesRows> 
    <tr *ngFor="let innerItem of project.projectServices"> 
     <td>{{innerItem.service.sku}}</td> 
     <td>{{innerItem.service.name}}</td> 
     <td>{{innerItem.unit}}</td> 
    </tr> 
    </ng-template> 
</tbody> 

或者,如果DTO的足够相似,则可以考虑共享多个视图逻辑:

<tbody> 
    <!-- You may want to perform the concatenation inside of the view model for additional clarity --> 
    <tr *ngFor="let innerItem of project.material_projects.concat(project.project_services)"> 
    <td>{{(innerItem.material || innerItem.service).sku}}</td> 
    <td>{{(innerItem.material || innerItem.service).name}}</td> 
    <td>{{innerItem.unit}}</td> 
    </tr> 
</tbody> 

编辑:

如果您想根据属性的存在使用不同的表格,那么您需要将您的*ngIf语句移动到<table>元素或直接子元素。根据您的意见,您可以尝试类似以下内容:

<div class="card-block" *ngFor="let project of projects | search : searchBOM"> 
    <ng-container *ngIf="getProjectType(project)"> 
    <h2 class="proj-name">{{ project.name | titlecase }}</h2> 

    <table *ngIf="getProjectType(project) === 'material'" class="table table-bordered table-striped"> 
     <thead> 
     <tr> 
      <th>Material SKU</th> 
      <th>Material Name</th> 
      <th>Unit</th> 
     </tr> 
     </thead> 
     <tbody> 
     <tr *ngFor="let innerItem of project.material_projects"> 
      <td>{{innerItem.material.sku}}</td> 
      <td>{{innerItem.material.name}}</td> 
      <td>{{innerItem.unit}}</td> 
     </tr> 
     </tbody> 
    </table> 

    <table *ngIf="getProjectType(project) === 'services'" class="table table-bordered table-striped"> 
     <thead> 
     <tr> 
      <th>Project SKU</th> 
      <th>Project Name</th> 
      <th>Unit</th> 
     </tr> 
     </thead> 
     <tbody> 
     <tr *ngFor="let innerItem of project.project_services"> 
      <td>{{innerItem.project.sku}}</td> 
      <td>{{innerItem.project.name}}</td> 
      <td>{{innerItem.unit}}</td> 
     </tr> 
     </tbody> 
    </table> 

    </ng-container> 
</div> 

组件代码:

export class ProjectComponent { 
    ... 
    public getProjectType(project: Project): 'material' | 'services' | null { 
     return project.material_projects.length > 0 ? 'material' 
      : project.project_services.length > 0 ? 'services' 
      : null; 
    } 
    ... 
} 

有很多方法可以做到这一点。另一种选择是在模板中使用switch语句,或者添加额外的子(“虚拟”)组件来处理行为。

+0

其实,material_projects和projects_services有不同的角色。如果他们既不是material_projects和project_services那么也不显示任何东西 –

+0

如何做出3个条件,如没有material_projects或project_services,那么不显示该特定项目? –

+0

@GraySingh,如果你需要添加第三个条件,那么你可以添加另一个'* ngIf'结构指令给父节点。查看修改。在Angular中有很多方法可以解决同样的问题,所以编写这个组件的方法有很多。您也可以考虑将事物(如项目显示)抽象为子组件。将内容分隔成更小的虚拟组件是'* ngFor'指令内容的常见模式。 –