如何在点击按钮时快速关闭弹出窗口？

Question

我已经创建了弹出窗口，其中有两个按钮。点击弹出窗口中的按钮时，我想关闭弹出窗口。

这是我的代码： FirstViewController：

@IBAction func bar_button(_ sender: UIBarButtonItem) { 

    let vc = storyboard?.instantiateViewController(withIdentifier: "SecondViewController") as! 
    SecondViewController 
    vc.preferredContentSize = CGSize(width: 200,height:80) 
    let navController = UINavigationController(rootViewController: vc) 
    navController.modalPresentationStyle = UIModalPresentationStyle.popover 

    let popover = navController.popoverPresentationController 
    popover?.delegate = self 
    popover?.barButtonItem = sender as! UIBarButtonItem 
    self.present(navController, animated: true, completion: nil) 

} 

SecondViewController：

@IBAction func second_button(_ sender: UIButton) { 
    //want to dismiss popover when button clicked 
     } 
@IBAction func second_button(_ sender: UIButton) { 
    //want to dismiss popover when button clicked 
     } 

Answer 1

呼叫

dismiss(animated: true, completion: nil) 

这些方法里面，这将解雇提出酥料饼。