如何添加逻辑运算符?
问题描述:
我一直在尝试Codecademy这个问题整天。我做的没有任何事情似乎有效。如何添加逻辑运算符?
说明: “添加一些if/else语句,以您的案件检查,看看一个条件和其他条件是否属实,还有一个条件或者其他条件是否真实使用& &和||至少。每一次。“
这是我以前输入的代码:
var user = prompt("What is your name?").toUpperCase();
switch(user) {
case 'Sam':
console.log("Hi, Sam");
break;
case 'John':
console.log("Hi, John");
break;
case 'Mary':
console.log("Hi, Mary");
break;
default:
console.log("I don't know you. What is your name?");
}
答
-
.toUpperCase()
转换一个字符串为大写字母,所以这将是 'SAM', '约翰' 等
更改它像这样:
String.prototype.capitalizeFirstLetter = function() {
return this.charAt(0).toUpperCase() + this.slice(1);
}
var user = prompt("What is your name?").capitalizeFirstLetter()
-
你需要测试什么条件?
switch(user) { case 'Sam': if (someCondition || anotherCondition) { // do something } else { // do something } console.log("Hi, Sam"); break; case 'John': console.log("Hi, John"); break; case 'Mary': console.log("Hi, Mary"); break; default: console.log("I don't know you. What is your name?”); }
答
您的代码没有任何if/else
语句。怎么样这样的事情:
var user = prompt("What is your name?").toUpperCase();
// If user is known, greet him
if (user === "SAM" || user === "JOHN" || user === "MARY") {
console.log("Hi, " + user)
}
// Otherwise apologize because we are polite
else {
console.log("Sorry " + user + ", I don't know you.");
}
// If user is neither John nor Sam, ask about them
if (user !== "JOHN" && user !== "SAM") {
console.log("By the way, how are John and Sam doing?");
}
+0
+我为了一个很好的例子和一个让我微笑的评论_'Otherwise道歉,因为我们很有礼貌'__ – blex 2015-03-31 19:24:07
它说“添加if/else语句”,所以添加这些。 – 2015-03-31 18:59:44
'user'永远不会等于这些名称之一,因为您输入的任何内容都设置为大写。 – blex 2015-03-31 19:00:09
我明白这只是一个演示应用程序而已,但“我不认识你,你叫什么名字?”在你刚刚问过之后......这很奇怪。 – zerkms 2015-03-31 19:00:29