单元阵列

Question

我创建的结构文件的单元阵列，像这样的例子：

>> res2 

res2 = 

    Columns 1 through 7 

    [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] 

    Columns 8 through 10 

    [1x1 struct] [1x1 struct] [1x1 struct] 



>> res2{1} 

ans = 

    nchi005_randchi005: 0.1061 
      nfdr_randfdr: 0.0011 
      nlgt_randlgt: 2.9517e-004 
     nphast_randphast: 0.6660 
      ndd_rand_dd: 0.0020 
    ndd_rand_dd_larger: 1 

    >> res2{1}.nlgt_randlgt 

ans = 

    2.9517e-004 


>> res{:}.nlgt_randlgt 
??? Bad cell reference operation. 

是否有一个方法可行访问RES2-cellarray的一次全nlgt_randlgt场？

Answer 1

您只需将res2从单元格阵列转换为结构数组（使用cell2mat）即可。然后你可以完全按照你想要的方式获得结构成员。以下是一个示例，其中cdat是包含两个成员的结构的单元阵列，s1和s2。

cdat = 

    [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] [1x1 struct] 

>> dat = cell2mat(cdat) 

dat = 

1x10 struct array with fields: 
    s1 
    s2 

>> [dat(:).s1] 

ans = 

    1  1  1  1  1  1  1  1  1  1 

Answer 2

您可以通过访问该单元：

cellfun(@(r) r.nlgt_randlgt, res2);