从Android设备上传文件到远程服务器
问题描述:
我已经检查了很多问题和答案,将数据上传到远程服务器,但大多数都使用已弃用的HttpClient。 我想上传一个简单的sqlite数据库文件,以后可以下载并重新安装应用程序时恢复。 我知道我应该使用Volley库,但我只知道如何使用JSONObject而不是文件。请帮忙。从Android设备上传文件到远程服务器
注意:该文件已被复制到我的外部存储器。
答
试试这个代码..
public int uploadFile(String sourceFileUri) {
String fileName = sourceFileUri;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
dialog.dismiss();
Log.e("uploadFile", "Source File not exist :"
+uploadFilePath + "" + uploadFileName);
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Source File not exist :"
+uploadFilePath + "" + uploadFileName);
}
});
return 0;
}
else
{
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name="uploaded_file";filename=""
+ fileName + """ + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.\n\n See uploaded file here : \n\n"
+" http://www.androidexample.com/media/uploads/"
+uploadFileName;
messageText.setText(msg);
Toast.makeText(UploadToServer.this, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("MalformedURLException Exception : check script url.");
Toast.makeText(UploadToServer.this, "MalformedURLException",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Got Exception : see logcat ");
Toast.makeText(UploadToServer.this, "Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
dialog.dismiss();
return serverResponseCode;
} // End else block
}
}
这是PHP代码:
<?php
$file_path = "uploads/";
$file_path = $file_path . basename($_FILES['uploaded_file']['name']);
if(move_uploaded_file($_FILES['uploaded_file'] ['tmp_name'], $file_path)) {
echo "success";
} else{
echo "fail";
}
?>
了解更多详情尝试this例子。
+0
它工作。起初它没有。但是当我在doInBackground AsyncTask中运行uploadFile()时,它就起作用了 – Mwas
答
您必须创建一个VolleyMultipartRequest。您可以在Working POST Multipart Request with Volley and without HttpEntity
中找到示例实现您在创建DataPart时需要输入文件类型,而重写getByteData()方法。
使用多部分实体 –
你能指导我一个例子或相同的教程。我是一个初学者 – Mwas
看到这个库https://github.com/gotev/android-upload-service。它支持多部分实体 – MRX