如何在数字猜测游戏循环时重新启动

问题描述：

我对此代码有问题。我看到的问题是，当用户运行代码并猜测正确或使用最大尝试次数时，while循环不会启动并允许游戏重新启动。我的想法是将计数器（尝试）重置为零并重新开始，但我只是以总分来获得退出消息。如何在数字猜测游戏循环时重新启动

int guess = 0; 
    int attempt = 0; 
    int number = new Random().nextInt(1000) + 1; 
    int scorePlayer = 0; int scoreComputer = 0; 
    boolean repeat; 

    System.out.println("Hello and welcome to the number guessing game."); 
    System.out.println("Please guess a number between 1 and 1000"); 


    while(repeat == true){ 
     do{ 
      Scanner scan = new Scanner(System.in); 
      guess = Integer.parseInt(scan.nextLine()); 
      System.out.println("The number you guessed is "+guess); 
      attempt++; 

      if(guess == number){ 
       System.out.println("Congratulations! You got it!!"); 
       scorePlayer++; 
       System.out.println("Would you like to play again? [YES/NO]"); 
       Scanner a = new Scanner(System.in); 
       String answer = a.nextLine().toUpperCase(); 
       if (answer != "YES"){ 
        //repeat = false; 
        System.out.println("Thank you for playing"); 
        System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server"); 
        if (scorePlayer<scoreComputer){ 
         System.out.println("Computer wins!"); 
        }else{ 
         System.out.println("You win!"); 
        }break; 
       }else{ 
        attempt = 0; 
       } 
      }else if(guess < number){ 
       System.out.println("That is incorrect, try a larger number"); 

      }else if(guess > number){ 
       System.out.println("That is incorrect, try a smaller number"); 

      }if(attempt == 10 && guess != number){ 
       System.out.println("That is the max number of guesses allowed"); 
       System.out.println("The number you were looking for is "+number); 
       scoreComputer++; 
       System.out.println("Would you like to play again? [YES/NO]"); 
       Scanner b = new Scanner(System.in); 
       String answer = b.nextLine().toUpperCase(); 
       if (answer != "YES"){ 
        //repeat = false; 
        System.out.println("Thank you for playing"); 
        System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server"); 
        if (scorePlayer<scoreComputer){ 
         System.out.println("Computer wins!"); 
        }else{ 
         System.out.println("You win!"); 
        }break; 
       }else{ 
        attempt = 0; 
       } 
      } 

     }while(guess != number || attempt == 0); 
     repeat = false; 
    }

假设你修正了编译器错误'while（repeat = true）'：你在第一个内部'do-while'循环完成之后直接''repeat'设置为'false'。那么外环的想法是什么呢？它只运行一次。 – AKSW

答

单个“=”是一个赋值操作符，只需将其更改为双“==”即可。

while(repeat == true)

这不能解决问题，这个问题不是由于那个错字导致的，所以我认为这个问题可能在别处。该代码不允许游戏在正确的数字被猜测或用户用完尝试后重新启动 – user3018640

答

除了UGUR说什么，你可以简单地做

while(repeat)

，因为重复是一个布尔变量（返回true或false）

答

检查的最后一行在外环你正在设置repeat=false。所以当你从内循环break，外while检查重复，这是每一次，除了第一次是错误的。

如何在数字猜测游戏循环时重新启动

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