我对输出感到困惑，因为它不会让我重新创建对象

Question

我试图解决一个问题，我尝试在绘制所有卡片后重置我的卡片组。当我到达甲板的末端时，我确实应该得到消息Deck is empty! You must recreate and reshuffle deck of cards!，但一旦甲板被重新创建并重新洗牌，它仍会不断显示此消息。

因此，我将Card对象传递给Deck类，其中以堆栈方式存储在数组中。

为什么我得到这样的输出，我确实重置了一副牌？

deal, bet, hit, stay, split, leave: deal 

Drawing Player's card... 9 ♥ 
Drawing Dealer's card... A ♣ 
Drawing Player's card... 7 ♦ 
Drawing Dealer's card... K ♦ 

Dealers Hand: K_♦ A_♣ = 21 
Players Hand: 7_♦ 9_♥ = 16 

Dealer has BLACKJACK! 

deal, bet, hit, stay, split, leave: deal 

Deck is empty! You must recreate and reshuffle deck of cards! 
Creating deck... 
Shuffling deck... 
Drawing Player's card... 7 ♥ 
Drawing Dealer's card... 5 ♥ 
Drawing Player's card... K ♠ 
Drawing Dealer's card... 6 ♦ 

Dealers Hand: 6_♦ 5_♥ = 11 
Players Hand: K_♠ 7_♥ = 17 

deal, bet, hit, stay, split, leave: deal 

Deck is empty! You must recreate and reshuffle deck of cards! 
Creating deck... 
Shuffling deck... 
Drawing Player's card... Q ♦ 
Drawing Dealer's card... 9 ♥ 
Drawing Player's card... 8 ♥ 
Drawing Dealer's card... 10 ♠ 

Dealers Hand: 10_♠ 9_♥ = 19 
Players Hand: 8_♥ Q_♦ = 18 

deal, bet, hit, stay, split, leave: deal 

Deck is empty! You must recreate and reshuffle deck of cards! 
Creating deck... 
Shuffling deck... 
Drawing Player's card... 3 ♣ 
Drawing Dealer's card... 6 ♠ 
Drawing Player's card... 4 ♠ 
Drawing Dealer's card... K ♠ 

Dealers Hand: K_♠ 6_♠ = 16 
Players Hand: 4_♠ 3_♣ = 7 

deal, bet, hit, stay, split, leave: 

这是我如何重置我的扑克牌：

private static Deck createDeck(Deck deck) 
{ 
    System.out.println("Creating deck..."); 
    deck = new Deck(DECKSIZE); 
    deck.createDeck(); 

    System.out.println("Shuffling deck..."); 
    deck.shuffleDeck(); 

    return deck; 
} 

这是我如何检查，如果甲板为空：

private static Deck checkDeck(Deck deck) 
{ 
    if(deck == null) 
     return createDeck(deck); 
    if(deck.isEmpty()) 
    { 
     deck = new Deck(DECKSIZE); 
     System.out.print("Deck is empty! You must recreate and reshuffle deck of cards!\n"); 
     return createDeck(deck); 
    } 
    else 
     return deck; 
} 

我检查之前每次甲板我画一张卡片：

public static void drawFromDeck(Deck deck, Hand hand) 
{ 
    deck = checkDeck(deck); 

    Card temp = new Card(deck.pop()); 
    System.out.println("Drawing " + hand.getName() + "'s card... " + temp.toString()); 
    hand.insert(temp); 

    System.out.print("\n"); 
} 

initialDraw（）

private static void initialDraw(Deck deck, Hand player, Hand dealer) 
{ 
    deck = checkDeck(deck); 
    drawFromDeck(deck, player); // drawing players card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, dealer); // drawing dealers card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, player); // drawing players card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, dealer); // drawing dealers card 

    System.out.print("Dealers Hand:"); 
    dealer.displayHand(); 
    System.out.print(" = " + dealer.getHandTotal() + "\n"); 
    System.out.print("Players Hand:"); 
    player.displayHand(); 
    System.out.print(" = " + player.getHandTotal() + "\n"); 

    checkInitialDraw(player, dealer); 
} 

Answer 1

有几个作用域问题（在甲板变量）。

总之，这是错误的类型：用于获取代码工作，但是，你可以提高你的代码

void createObj(MyObject objt) 
{ 
    objt = new MyObject(); //Local Scope 
} 
//Caller 
MyObject obj = null; 
createObj(obj); // <-- New object will be created only within the function, obj will remain unaffected. 
// obj is still null; 

我建议这些变化（WRT http://ideone.com/S4Yv3l）。

i）更改createDeck的签名。

private static Deck createDeck() 
    { 
     System.out.println("Creating deck..."); 
     Deck deck = new Deck(DECKSIZE); 
     deck.createDeck(); 

     System.out.println("Shuffling deck..."); 
     deck.shuffleDeck(); 

     return deck; 
    } 

ⅱ） CheckDeck

private static Deck checkDeck(Deck deck) 
    { 
     if(deck == null) 
      return createDeck(); 

     if(deck.isEmpty()) 
     { 
      System.out.print("Deck is empty! You must recreate and reshuffle deck of cards!\n"); 
      return createDeck(); 
     } 

     return deck; 
    } 

ⅲ） InitialDraw

private static Deck initialDraw(Deck deck, Hand player, Hand dealer) 
{ 
    deck = checkDeck(deck); 
    drawFromDeck(deck, player); // drawing players card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, dealer); // drawing dealers card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, player); // drawing players card 
    deck = checkDeck(deck); 
    drawFromDeck(deck, dealer); // drawing dealers card 

    System.out.print("Dealers Hand:"); 
    dealer.displayHand(); 
    System.out.print(" = " + dealer.getHandTotal() + "\n"); 
    System.out.print("Players Hand:"); 
    player.displayHand(); 
    System.out.print(" = " + player.getHandTotal() + "\n"); 

    checkInitialDraw(player, dealer); 
    return deck; 
} 

ⅳ）在主：

deck = initialDraw(deck, playersHand, dealersHand); 

我建议只对一组事物进行更改，您可以使用相同的原则来组织其他功能。

Answer 2

if(deck == null) 
    return createDeck(deck); 
else if(deck.isEmpty()) 
{ 
    deck = new Deck(DECKSIZE); 
    System.out.print("Deck is empty! You must recreate and reshuffle deck of cards!\n"); 
    return createDeck(deck); 
} 
else 
    return deck; 

}

试试这个