博特代码错误：预期的缩进块

问题描述：

，所以我现在有这样的代码，这使得一个很可能很可能对我的不和谐机器人，我有这个错误的地方说：“齿痕错误：预期和缩进块”博特代码错误：预期的缩进块

下面是我使用的代码（见https://hastebin.com/isageyoqih.py）

import discord 
import asyncio 
import random 
import pickle 
import os 

client = discord.Client() 

@client.event 
async def on_ready(): 
    print('Ready and with') 
    print(client.user.name) 

@client.event 
async def on_message(message): 
    if message.content.startswith('_whatcanyoudo?'): 
     msg = await client.send_message(message.channel, '```Heres what i can do :```') 
     await asyncio.sleep(0.5) 
     msg2 = await client.send_message(message.channel, '```For now, i can only do a thing called "flip a coin"```') 
     await asyncio.sleep(0.5) 
     msg3 = await client.send_message(message.channel, '```Bot powered by Ouindoze™, message will delete in 15 seconds```') 
     await asyncio.sleep(15) 
     await client.delete_message(msg) 
     await client.delete_message(msg2) 
     await client.delete_message(msg3) 


    elif message.content.startswith('_8ball'): 
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later']) 
    msg5 = await client.send_message(message.channel, 8ball) 

client.run('I obiously won't share the token duh xd')

Here is the error I got。

答

elif message.content.startswith('_8ball'): 
8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later']) 
msg5 = await client.send_message(message.channel, 8ball)

应该是（elif后注压痕）

elif message.content.startswith('_8ball'): 
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later']) 
    msg5 = await client.send_message(message.channel, 8ball)

，并顺便说一下，8ball是非法的名字一个变量作为变量名已经开始与信或下划线符号（_）。

注：长的列表可以在多行以提高可读性分裂：

ball = random.choice([ 
     'It is certain', 
     'As i see it, yes', 
     'Dont count on it', 
     'Without a doubt', 
     'Definitely', 
     'Very doubtful', 
     'Outlook not so good', 
     'My sources say no', 
     'My reply is no', 
     'Most likely', 
     'You may rely on it', 
     'Ask again later' 
     ])

这样的问题应该已经被评论和投票结束为一个简单的印刷错误。由于这个问题不会对未来的读者有所帮助，除了OP – abccd

非常感谢，我已经在这个2小时xD – Ouindoze

答

elif message.content.startswith('_8ball'): 
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later']) 
    msg5 = await client.send_message(message.channel, 8ball)

那么它到底是什么错误消息说：缩进它。

博特代码错误：预期的缩进块

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