Python - Tkinter - 来自StringVar的标签文本不会显示/更新
问题描述:
我试图转换我以前写过的一个简单的命令行程序来创建GUI。在开始将事物添加到我的现有/工作代码之前,我想玩弄在Tkinter中构建GUI。我终于开始取得进展,只要让事情显示我希望他们如何,直到我得到的小部件,我希望他们的显示文本取决于变量的内容变化。Python - Tkinter - 来自StringVar的标签文本不会显示/更新
从我在这里阅读的文档以及各种文档集中,要做到这一点的方法是我试图做的StringVar
,但是当我运行程序时,status_msg
标签小部件的文本根本没有出现。我尝试过在一些地方放置一个set()调用来更新变量,当它看起来更新变量时,标签并没有显示在窗口中。最后,我尝试添加一个“添加键”按钮调用的函数来强制设置调用,并尝试使标签显示,但它仍然不起作用,尽管它确实打印了我期望的控制台。
我搞不清楚我做错了什么。这里是我的代码:
import tkinter as tk
numkeys = 0
keystring = str(numkeys) + " entries ready for parsing"
class Application(tk.Frame):
def __init__(self, master=None):
tk.Frame.__init__(self, master)
self.grid()
self.createWidgets()
def createWidgets(self):
self.numkeys = tk.StringVar()
self.numkeys.set(keystring)
api_frame = tk.LabelFrame(self, text="Key Entry", padx = 5, pady = 5)
api_frame.grid(padx = 10, pady = 10)
key1_lbl = tk.Label(api_frame, text = "Entry 1:", anchor = tk.W)
key1_lbl.grid(row = 0, column = 0)
self.key = tk.Entry(api_frame, width = 18)
self.key.grid(row = 0, column = 1)
key2_lbl = tk.Label(api_frame, text="Entry 2:")
key2_lbl.grid(row = 0, column = 2, padx = 5)
self.key2 = tk.Entry(api_frame, width = 45)
self.key2.grid(row = 0, column = 3, padx = 2, columnspan = 3)
status_msg = tk.Label(api_frame, textvariable = self.numkeys.get())
status_msg.grid(row = 1, column = 0, columnspan = 3)
btn_submit = tk.Button(api_frame, text="Add Key", width = 12, command = self.test)
btn_submit.grid(row = 1, column = 4, pady = 5)
btn_start = tk.Button(api_frame, text="Parse Keys", width = 12, command = None)
btn_start.grid(row = 1, column = 5, pady = 5)
#self.numkeys.set(keystring)
def test(self):
self.numkeys.set(keystring)
root.update_idletasks()
print("test function ran")
print(app.numkeys.get())
root = tk.Tk()
app = Application(master=root)
app.master.title('Tk test')
app.mainloop()
答
通过
textvariable = self.numkeys
也做了更换
!在看到这是多么简单之后,我感到有点愚蠢,但非常抱怨。谢谢! – Prodigal