python 3.2语法错误：无效语法
问题描述：
任何人都可以在这个Python 3.2代码中找到语法错误？python 3.2语法错误：无效语法
import math
import numpy
vinf = 10
vfr = 4
x = numpy.linspace(-10,10,50)
y = numpy.linspace(-10,10,50)
a = numpy.zeros(shape=(len(x),len(y)))
b = numpy.zeros(shape=(len(x),len(y)))
u = numpy.zeros(shape=(len(x),len(y)))
v = numpy.zeros(shape=(len(x),len(y)))
p = numpy.zeros(shape=(len(x),len(y)))
s = numpy.zeros(shape=(len(x),len(y)))
for i in range (0,len(x)):
for j in range (0,len(y)):
a[i][j]=x[i]
b[i][j]=y[j]
for i in range (0,len(x)):
for j in range (0,len(y)):
v[i][j] = (vfr/(2*math.pi))*math.pow((b[i][j]+.0047)/(a[i][j]+.05)+(b[i][j]+.0517)/(a[i][j]+.2084)+(b[i][j]-.0271)/(a[i][j]+.2084)+(b[i][j]+.0583)/(a[i][j]+.525)+(b[i][j]-.0228)/(a[i][j]+.525)+(b[i][j]+.0242)/(a[i][j]+.8417)+(b[i][j]-.0087)/(a[i][j]+.8417),-2)*((b[i][j]+.0047)/(math.pow(a[i][j]+.05,2)*(1+math.pow((b[i][j]+.0047)/(a[i][j]+.05),2)))+(b[i][j]+.0517)/(math.pow(a[i][j]+.2084,2)*(1+math.pow((b[i][j]+.0517)/(a[i][j]+.2084),2)))+(b[i][j]-.0271)/(math.pow(a[i][j]+.2084,2)*(1+math.pow((b[i][j]-.0271)/(a[i][j]+.2084),2)))+(b[i][j]+.0583)/(math.pow(a[i][j]+.525,2)*(1+math.pow((b[i][j]+.0583)/(a[i][j]+.525),2)))+(b[i][j]-.0228)/(math.pow(a[i][j]+.525,2)*(1+math.pow((b[i][j]-.0228)/(a[i][j]+.525),2)))+(b[i][j]+.0242)/(math.pow(a[i][j]+.8417,2)*(1+math.pow((b[i][j]+.0242)/(a[i][j]+.8417),2)))+(b[i][j]-.0087)/(math.pow(a[i][j]+.8417,2)*(1+math.pow((b[i][j]+.0087)/(a[i][j]+.8417),2))))
u[i][j] = vinf+(vfr/(2*math.pi))*math.pow((b[i][j]+.0047)/(a[i][j]+.05)+(b[i][j]+.0517)/(a[i][j]+.2084)+(b[i][j]-.0271)/(a[i][j]+.2084)+(b[i][j]+.0583)/(a[i][j]+.525)+(b[i][j]-.0228)/(a[i][j]+.525)+(b[i][j]+.0242)/(a[i][j]+.8417)+(b[i][j]-.0087)/(a[i][j]+.8417),-2)*(1/((a[i][j]+.05)*(1+math.pow((b[i][j]+.0047)/(a[i][j]+.05),2)))+1/((a[i][j]+.2084)*(1+math.pow((b[i][j]+.0517)/(a[i][j]+.2084),2)))+1/((a[i][j]+.2084)*(1+math.pow((b[i][j]-.0271)/(a[i][j]+.2084),2)))+1/((a[i][j]+.525)*(1+math.pow((b[i][j]+.0583)/(a[i][j]+.525),2)))+1/((a[i][j]+.525)*(1+math.pow((b[i][j]-.0228)/(a[i][j]+.525),2)))+1/(a[i][j]+.8417)*(1+math.pow((b[i][j]+.0242)/(a[i][j]+.8417),2)))+1/((a[i][j]+.8417)*(1+math.pow((b[i][j]+.0087)/(a[i][j]+.8417),2))))
p[i][j] = 1-math.pow(math.sqrt(math.pow(u[i][j],2)+math.pow(v[i][j],2)),2)
file = open("data.dat","w")
file.write('title = "Driven Cavity"\r\n')
file.write('variables = "x", "y", "u", "v", "p"\r\n')
file.write('ZONE T="All"\r\n')
file.write(' I={}'.format(len(x)))
file.write(' J={}'.format(len(x)))
file.write(' K=1')
file.write(' ZONETYPE=Ordered\r\n')
file.write(' DATAPACKING=POINT\r\n')
for i in range (0,len(x)):
for j in range (0,len(y)):
file.write('{}\t'.format(a[i][j]))
file.write('{}\t'.format(b[i][j]))
file.write('{}\t'.format(u[i][j]))
file.write('{}\t'.format(v[i][j]))
file.write('{}\t\n'.format(p[i][j]))
file.close()
错误说，这是在U [i] [j] =行 结束它可能是一个括号或东西，我只是不能看到它。 我从昨晚5点开始一直在努力，现在是第二天下午3:40。
答
将它粘贴到vim中，并突出显示最后一个字符，至少有一个额外的关闭字母。但是，我建议将其分解为多行，以便可以手动进行调试。出于可读性的原因，长线不是任何语言的好主意。
答
额外)在一行的末尾，这个替换该行：
u[i][j] = vinf+(vfr/(2*math.pi))*math.pow((b[i][j]+.0047)/(a[i][j]+.05)+(b[i][j]+.0517)/(a[i][j]+.2084)+(b[i][j]-.0271)/(a[i][j]+.2084)+(b[i][j]+.0583)/(a[i][j]+.525)+(b[i][j]-.0228)/(a[i][j]+.525)+(b[i][j]+.0242)/(a[i][j]+.8417)+(b[i][j]-.0087)/(a[i][j]+.8417),-2)*(1/((a[i][j]+.05)*(1+math.pow((b[i][j]+.0047)/(a[i][j]+.05),2)))+1/((a[i][j]+.2084)*(1+math.pow((b[i][j]+.0517)/(a[i][j]+.2084),2)))+1/((a[i][j]+.2084)*(1+math.pow((b[i][j]-.0271)/(a[i][j]+.2084),2)))+1/((a[i][j]+.525)*(1+math.pow((b[i][j]+.0583)/(a[i][j]+.525),2)))+1/((a[i][j]+.525)*(1+math.pow((b[i][j]-.0228)/(a[i][j]+.525),2)))+1/(a[i][j]+.8417)*(1+math.pow((b[i][j]+.0242)/(a[i][j]+.8417),2)))+1/((a[i][j]+.8417)*(1+math.pow((b[i][j]+.0087)/(a[i][j]+.8417),2)))
这将是有益的，如果你能提供追踪/错误消息，并且还确定你在你的源注释提线清单。 – Levon
它可能也有助于使用突出显示匹配圆括号的文本编辑器。 – fferen
更有帮助的将是PEP 8（http://www.python.org/dev/peps/pep-0008/），该行有** 734 **个字符 – Levon