Python - 电报机器人的国际化

Question

我使用Python gettext将我的电报机器人消息转换为pt_BR或将它们留在en_US中。这是我的代码：

# Config the translations 
lang_pt = gettext.translation("pt_BR", localedir="locale", languages=["pt_BR"]) 
def _(msg): return msg 

# Connecting to Redis db 
db = redis.StrictRedis(host="localhost", port=6379, db=0) 


def user_language(func): 
    @wraps(func) 
    def wrapped(bot, update, *args, **kwargs): 
     lang = db.get(str(update.message.chat_id)) 

     if lang == b"pt_BR": 
      # If language is pt_BR, translates 
      _ = lang_pt.gettext 
     else: 
      # If not, leaves as en_US 
      def _(msg): return msg 

      result = func(bot, update, *args, **kwargs) 
      return result 
     return wrapped 

@user_language 
def unknown(bot, update): 
    """ 
     Placeholder command when the user sends an unknown command. 
    """ 
    msg = _("Sorry, I don't know what you're asking for.") 
    bot.send_message(chat_id=update.message.chat_id, 
        text=msg) 

但是，即使语言是pt_BR，文本仍然是en_US。看起来函数_()（第3行）的第一个声明立即翻译所有消息，并且即使装饰器中的函数发生更改，消息也不会再被翻译。

如何强制消息在装饰器中再次翻译？

Answer 1

解决！

我只是忘记宣布_（）为全球性的。这里是正确的代码：

def user_language(func): 
    @wraps(func) 
    def wrapped(bot, update, *args, **kwargs): 
     lang = db.get(str(update.message.chat_id)) 

     global _ 

     if lang == b"pt_BR": 
      # If language is pt_BR, translates 
      _ = lang_pt.gettext 
     else: 
      # If not, leaves as en_US 
      def _(msg): return msg 

     result = func(bot, update, *args, **kwargs) 
     return result 
    return wrapped