Android - Firebase推送通知不起作用
问题描述:
我已经完全按照Google教程中的提示创建并设置了Firebase控制台。我也在我的项目中实施了服务。虽然我从Firebase控制台发送邮件,但未在我的应用中收到。当我尝试使用单个设备发送时,它显示“未注册的注册令牌”。Android - Firebase推送通知不起作用
这里是我的MyFirebaseInstanceIDService:
public class MyFirebaseInstanceIDService extends FirebaseInstanceIdService {
@Override
public void onTokenRefresh() {
//Getting registration token
String refreshedToken = FirebaseInstanceId.getInstance().getToken();
System.out.println("TOKEN::" + refreshedToken);
//Displaying token on logcat
SmartApplication.REF_SMART_APPLICATION.writeSharedPreferences("regId", refreshedToken);
// SharedPreferences pref = getApplicationContext().getSharedPreferences(Config.SHARED_PREF, 0);
// SharedPreferences.Editor editor = pref.edit();
// editor.putString("regId", refreshedToken);
// editor.commit();
}
}
这里是我的MyFirebaseMessagingService:
public class MyFirebaseMessagingService extends FirebaseMessagingService {
private static final String TAG = "MyFirebaseMsgService";
private static int count = 0;
String TYPE = "type";
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
//Displaying data in log
//It is optional
System.out.println("data getting");
Log.d(TAG, "Notification Message TITLE: " + remoteMessage.getNotification().getTitle());
Log.d(TAG, "Notification Message BODY: " + remoteMessage.getNotification().getBody());
Log.d(TAG, "Notification Message DATA: " + remoteMessage.getData().toString());
//Calling method to generate notification
//remoteMessage.getNotification().getBody()
sendNotification(remoteMessage.getNotification().getTitle(),
remoteMessage.getNotification().getBody(), remoteMessage.getData());
}
//This method is only generating push notification
//It is same as we did in earlier posts
private void sendNotification(String messageTitle, String messageBody, Map<String, String> row) {
PendingIntent contentIntent = null;
try {
Intent groupDetailIntent = new Intent(this, UnanimousHomeActivity.class);
contentIntent = PendingIntent.getActivity(this, (int) (Math.random() * 100),
groupDetailIntent, PendingIntent.FLAG_UPDATE_CURRENT);
} catch (Exception e) {
e.printStackTrace();
}
Uri defaultSoundUri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
.setSmallIcon(R.mipmap.ic_launcher)
.setContentTitle(messageTitle)
.setContentText(messageBody)
.setAutoCancel(true)
.setSound(defaultSoundUri)
.setContentIntent(contentIntent);
NotificationManager notificationManager =
(NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(count, notificationBuilder.build());
count++;
}
}
由于图4天,我已经stucked,请别人帮我这里没有发现任何逻辑问题,一些不寻常的事情正在发生,而整合推动。
答
public class MyFirebaseMessagingService extends FirebaseMessagingService {
private static final String TAG = MyFirebaseMessagingService.class.getSimpleName();
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
Log.e(TAG, "From: " + remoteMessage.getFrom());
// Check if message contains a data payload.
if (remoteMessage.getData().size() > 0) {
Log.e(TAG, "Message data: " + remoteMessage.getData().toString());
}
if (remoteMessage.getNotification() != null) {
Log.e(TAG, "Message data: " + remoteMessage.getData().toString());
sendnotification(remoteMessage.getNotification().getBody());
}
}
private void sendnotification(String body) {
Intent intent = new Intent(this,MainActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
PendingIntent pendingIntent = PendingIntent.getActivity(this,0,intent,PendingIntent.FLAG_ONE_SHOT);
Uri notificationsound = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
.setSmallIcon(R.mipmap.ic_launcher)
.setContentTitle("Emoji Keyboard")
.setDefaults(-1)
.setContentText(body)
.setVibrate(new long[] { 1000, 1000, 1000, 1000, 1000 })
.setSound(notificationsound)
.setAutoCancel(true)
.setContentIntent(pendingIntent);
NotificationManager notificationManager = (NotificationManager)getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(0,notificationBuilder.build());
}
}
并在此之后在舱单补充一点:
<!-- Firebase Notifications -->
<service android:name=".services.MyFirebaseMessagingService">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
<service android:name=".services.MyFirebaseInstanceIDService">
<intent-filter>
<action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
</intent-filter>
</service>
<!-- ./Firebase Notifications -->
答
您已经成功获得令牌后,请确保您已经正确发送到您的服务器。
尝试recommended action为无效登记令牌:
检查登记的格式令牌传递给服务器。确保它与客户端应用程序从注册Firebase通知时收到的注册令牌相匹配。不要截断或添加其他字符。
欲了解更多信息,请参阅此documentation。
答
代码在我的应用程序工作正常
添加googleservices-JSON文件从火力创建应用文件夹,并 清单中
<service
android:name=".MyFirebaseMessagingService">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT"/>
</intent-filter>
</service>
<service
android:name=".MyFirebaseInstanceIDService">
<intent-filter>
<action android:name="com.google.firebase.INSTANCE_ID_EVENT"/>
</intent-filter>
</service>
加服去之前,不得不派出由谷歌控制台测试推如果没有,则点击链接 - > https://console.firebase.google.com 然后选择您的项目。选择您的项目后,点击导航抽屉列表左侧的通知,并发送测试推送链接 记得在发送测试推送您的设备应该在后台或关闭.. – yash786
尝试使用工具 - > Firebase - >云消息它可以帮助你找到缺失的论点 –
这些所有的事情我已经尝试过,但仍然没有成功。 –