PHP - 正确显示来自MySQL的结果

Question

我只是想知道是否有办法显示这一个接一个，而不是第一个数量比日期。

$apaidString = $apaid; 
$daterString = $dater; 
$apaidArray = explode(',', $apaidString); 
$daterArray = explode(',', $daterString); 

<?php foreach($apaidArray as $apaid_Array){ 
echo trim($apaid_Array,",").'<br>';}?> 
<?php foreach($daterArray as $dater_Array){ 
echo trim($dater_Array,",").'<br>';}?> 

该代码会显示：

50 
60 
10 
11-11-2016 
12-11-2016 
14-11-2016 

什么，我需要将是：

50 11-11-2016 
60 12-11-2016 
10 14-11-2016 

我从一个MySQL得到的值。

Answer 1

步行两个数组在同一时间：

<?php 
$apaidString = "50,60,10"; 
$daterString = "11-11-2016,12-11-2016,14-11-2016"; 
$apaidArray = explode(',', $apaidString); 
$daterArray = explode(',', $daterString); 

for ($i = 0; $i < count($apaidArray); $i++) 
{ echo $apaidArray[$i].'<br>'; 
    echo $daterArray[$i].'<br>'; 
} 
?> 

结果是：

50 
11-11-2016 
60 
12-11-2016 
10 
14-11-2016 

Answer 2

我认为你可以做到这样的，但我不知道这是更好的办法

foreach($apaidArray as $key_array => $apaid_Array) 
{ 
    echo trim($apaid_Array,",").' '.trim($daterArray[$key_array],",") .'</br>'; 
} 

输出：

50 11-11-2016 
60 12-11-2016 
10 14-11-2016 

，而不是

foreach($apaidArray as $apaid_Array){ 
echo trim($apaid_Array,",").'<br>';} 
foreach($daterArray as $dater_Array){ 
echo trim($dater_Array,",").'<br>';} 

，你可以直接做

$apaidArray = explode(',', $apaid); 
$daterArray = explode(',', $dater); 

代替

$apaidString = $apaid; 
$daterString = $dater; 
$apaidArray = explode(',', $apaidString); 
$daterArray = explode(',', $daterString);