查找并替换红宝石，除了一些短语文本文件

Question

我很确定我错了。但我希望这个程序能够通过“phone_numbers.txt”运行，并取代除["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"]之外的任何重复内容。此代码的结果完全不是。没有改变。有小费吗？

file_names = ['phone_numbers.txt'] 
    file_names.each do |file_name| 
     words_to_exclude = ["Employee Marked Urgency as: low", "Employee Marked Urgency as: high"] 
     text = File.read(file_name) 
     lines = text.split("\n") 
     new_contents = lines.uniq.reject do |word| 
     words_to_exclude.include? word 
     end.join("\n") 
     File.open(file_name, "w") { |file| file.puts new_contents } 
    end 

Answer 1

我不知道我的理解是正确的，但使用Array#uniq与块应该做的伎俩：

require 'digest/sha1' # to generate uniqs 

file_names = ['phone_numbers.txt'] 
words_to_exclude = ["Employee Marked Urgency as: low", 
        "Employee Marked Urgency as: high"] 

file_names.each do |file_name| 
    res = File.readlines(file_name).each_with_index.uniq do |s, idx| 
    words_to_exclude.include?(s) ? 
     Digest::SHA1.hexdigest(idx.to_s) : s 
    end.join("\n") 
    File.write(file_name, res) 
end 

这是怎么回事：如果我们从我们的名单中遇到的单词，我们生成无论如何，一个uniq足够的字符串是通过的;否则我们使用原始字符串进行比较。