使用GSON反序列化对象的JSON数组
问题描述:
这是一连串的反序列化问题,但我已经阅读了所有这些问题,无法找出解决方案。我需要获取所有的“entery” - >“content” - > $ t和“entery” - >“title” - >“$ t”,但是在CategoryDeserializer()中,我得到的JsonArray是NULL。我已经指出“< ====”代码的一部分。使用GSON反序列化对象的JSON数组
错误消息:
尝试上的空对象引用调用接口方法 'java.util.Iterator的 java.util.List.iterator()'
我有JSON那看起来是这样的:
{ "feed":{
"id":{ ... },
"author":[ ... ],
"entry":[
{
"id":{ },
"updated":{ },
"category":[ ],
"title":{
"type":"text",
"$t":"A1 },
"content":{
"type":"text",
"$t":"test"
},
"link":[ ]
},
{ ... },
{ ... },
{ ...},
]
}
}
这是我的代码部分,我尝试反序列化“entery”:
String json = response.body().toString();
Type listType = new TypeToken<List<Entry>>() {
}.getType();
Gson gson = new GsonBuilder().registerTypeAdapter(listType, new CategoryDeserializer()).create();
List<Entry> list = gson.fromJson(json, listType);
for (Entry entry : list) {
Log.i("MainActivity", "Content: " + entry.getContent());}
凡CategoryDeserializer()看起来是这样的:
public class CategoryDeserializer implements JsonDeserializer<List<Entry>> {
public List<Entry> deserialize(JsonElement je, Type type, JsonDeserializationContext jdc) throws JsonParseException {
JsonArray entry = je.getAsJsonObject().getAsJsonArray("entry"); //<==== here I get that entry is null but je has a value
ArrayList<Entry> myList = new ArrayList<Entry>();
for (JsonElement e : entry) {
myList.add((Entry) jdc.deserialize(e, Entry.class));
}
return myList;}
我的Entry类:
public class Entry {
private Id_ id;
private Updated_ updated;
private List<Category_> category = null;
private Title_ title;
private Content content;
private List<Link_> link = null;
//getters and setters
public Id_ getId() {
return id;
}
public void setId(Id_ id) {
this.id = id;
}
public Updated_ getUpdated() {
return updated;
}
public void setUpdated(Updated_ updated) {
this.updated = updated;
}
public List<Category_> getCategory() {
return category;
}
public void setCategory(List<Category_> category) {
this.category = category;
}
public Title_ getTitle() {
return title;
}
public void setTitle(Title_ title) {
this.title = title;
}
public Content getContent() {
return content;
}
public void setContent(Content content) {
this.content = content;
}
public List<Link_> getLink() {
return link;
}
public void setLink(List<Link_> link) {
this.link = link;
}
}
编辑:我已经声明和实例化。
答
我很复杂的事情并不复杂。所有我需要做的就是这样的:
String json = response.body().toString();
Gson mGson = new Gson();
//where Example is the root of JSON
Example rsp = mGson.fromJson(json, Example.class);
//Entry is the list I needed to access
List <Entry> listOfEntrys= rsp.getFeed().getEntry();
//get value
Log.i("MainActivity", "listaEntrya " + listOfEntrys.get(0).getTitle().get$t());
你看到了这个问题:HTTP://stackoverflow.com/questions/2864370/how-do-i-use-googles-gson-api-to-deserialize- json-properly – Milaci
你可以使用this> Response response = new Gson()。fromJson(s.toString(),Entry.class); –
但是,如果您可以完全显示json数据,那将会很有帮助。 –