Python：与文件操作操作有关的错误

Question

我通过json循环并写入文件并将其传递给另一个使用curl命令上载的函数。 以下是错误消息我得到：

Traceback (most recent call last): 
File "D:\python_ws\test.py", line 33, in <module> 
main((sys.argv[1:])) 
File "D:\python_ws\test.py", line 30, in main 
upload_file_bams(out_file) 
File "D:\python_ws\test.py", line 7, in upload_file 
file = open(rel_file).read() 
TypeError: coercing to Unicode: need string or buffer, file found 

我尝试不同的方法，但好像我在这里缺少一些基本知识。任何帮助表示赞赏。

这里是我的代码：

#!/usr/bin/env python 
import urllib2,json,sys,requests,subprocess,os 

def upload_file(rel_file): 
    url = "https://localhost:8080/artifactory/list/default.generic.local/ct/releases/" 
    user = "john.smith" 
    file = open(rel_file).read() 
    cmd = 'curl --verbose --user %s --upload-file %s %s' %(user,file,url) 
    print 'trying to execute %s' % cmd 
    x = subprocess.Popen('cmd', shell=True) 
    #subprocess.call('cmd', shell=True) 
    retval = x.wait() 

def main(argv): 
    #environment 
    env = sys.argv[1] 
    rel_name=sys.argv[2] 
    consul_url=("http://localhost:9090") % (env) 
    list_services = "/v1/catalog/services" 
    services_url = consul_url+list_services 
    list_of_services = urllib2.urlopen(services_url).read() 
    each_service = json.loads(list_of_services) 
    #to remove keys with blank values 
    newdict = dict([(vkey,vdata) for vkey, vdata in each_service.iteritems() if(vdata) ]) 
    try: 
     out_file = open(rel_name,"wb") 
     json.dump(newdict,out_file, indent=4) 
    finally: 
     out_file.close() 
    #uploading release json file to BAMS 
    upload_file(out_file) 

if __name__ == "__main__": 
     main((sys.argv[1:])) 

Answer 1

当你调用upload_file()，你通过它out_file这是file而不是string（文件名）类型。函数open()需要为第一个参数指定要打开的文件名。