如何解决System.Drawing中 - 参数无效

Question

如何解决System.Drawing中参数无效 当我使用代码：

string img2 = "http://13.228.146.249:8080/jcr/groups/629.png; 
byte[] toBytes = Encoding.ASCII.GetBytes(img2); 
if (toBytes != null) 
{ 
    MemoryStream ms = new MemoryStream(toBytes); 
    ms.Position = 0; 
    picboxserver.Image = Image.FromStream(ms); 
} 

picboxserver是PictureBox的类型。

Answer 1

你想在http://13.228.146.249:8080/jcr/groups/629.png里面你的PictureBox？在这种情况下，只需使用Load()-Function：

picboxserver.Load("http://13.228.146.249:8080/jcr/groups/629.png");