我的程序的逻辑有什么问题？

问题描述：

我的程序的逻辑有什么问题。由于某种原因，当我在玩家之间轮流转圈时，第二回合转瞬即逝，它会跳过它，并且游戏似乎被拖动了一步。即使我将它声明为主函数之上，数组是否更改？ tictactoe游戏的位置是我的程序的逻辑有什么问题？

1 | 2 | 3

4 | 5 | 6

6 | 8 | 9

代码

#include <stdio.h> 
int check(char player); 
void move(char player); 
void outprint(void); 
char board[3][3] ; 



int main(void) 
{ 
int first; 
char player1, player2; 

     printf("Player 1: Choose your symbol: \n"); 
     player1 = getchar(); 
     getchar(); 

     printf("Player 2: Choose your symbol: \n"); 
     player2 = getchar(); 
     getchar(); 



int i=0; 
int win; 
char turn; 
while(win == 0) 
{ 
     if((i%2) == 0){ 
       turn = player1; 
       move(player1); 
       win = check(player1); 
       outprint();} 
     else { 
       turn = player2; 
       move(player2); 
       win = check(player2); 
       outprint();} 
     i++; 
} 

     if (i == 8) 
       printf("its a tie"); 
     else 
       printf("the winner is %c", turn); 

return 0; 
} 

/*printing the board that takes in a placement int*/ 
void outprint(void) 
{ 
     int r; 
     printf("\n"); 
     for (r = 0; r < 3; r++){ 
       printf(" %c | %c | %c \n" , board[r][0], board[r][2], board[r][3]); 
     if (r != 2) 
       printf("___________\n"); 
     } printf("\n"); 
return; 
} 

/*check to see if someone won*/ 
int check(char player) 
{ 
     int r, c; 

     for (r = 0 ; r <3 ; r++) 
     { 
       if ((board[r][0] == player) && (board[r][1] == player) && (board[r][2] == player)) 
         return 1; 
     } 

     for (c = 0 ; c <3 ; c++) 
     { 
       if ((board[0][c] == player) && (board[1][c] == player) && (board[2][c] == player)) 
         return 1; 
     } 

     if((board[0][0] == player) && (board[1][1] == player) && (board[2][2] == player)) 
       return 1; 

     if((board[0][2] == player) && (board[1][1] == player) && (board[2][0] == player)) 
       return 1; 

     return 0; 
} 


void move(char player) 
{ 
     int place; 
     printf("player %c, enter placement: \n", player); 
     scanf("%d", &place); 

     if (place == 1) 
       board[0][0] = player; 
     else if (place == 2) 
       board[0][1] = player; 
     else if (place == 3) 
       board[0][2] = player; 

     else if (place == 4) 
       board[1][0] = player; 
     else if (place == 5) 
       board[1][1] = player; 
     else if (place == 6) 
       board[1][2] = player; 

     else if (place == 7) 
       board[2][0] = player; 
     else if (place == 8) 
       board[2][1] = player; 
     else if (place == 9) 
       board[2][2] = player; 
}

输出

Player 1: Choose your symbol: 
x 
Player 2: Choose your symbol: 
o 
player x, enter placement: 
1 

x | | 
___________ 
    | | 
___________ 
    | | 

player o, enter placement: 
2 

x | | 
___________ 
    | | 
___________ 
    | | 

player x, enter placement: 
3 

x | x | 
___________ 
    | | 
___________ 
    | | 

player o, enter placement: 
4 

x | x | o 
___________ 
o | | 
___________ 
    | | 

player x, enter placement: 
5 

x | x | o 
___________ 
o | | 
___________ 
    | | 

player o, enter placement: 
6 

x | x | o 
___________ 
o | o | 
___________ 
    | | 

player x, enter placement: 
7 

x | x | o 
___________ 
o | o | x 
___________ 
x | | 

the winner is x

答

尝试增加的getchar（）在你的scanf（“％d “，&地方）在你的move（）函数中，就像你在第一个输入项中做的那样：

void move(char player) 
{ 
    int place; 
    printf("player %c, enter placement: \n", player); 
    scanf("%d", &place); 
    getchar();

答

看起来你需要将板初始化为空格。

char board[3][3] = { " ", " ", " " };

它看起来像你没有打印任何东西。可能来自未初始化数据的非可打印垃圾。

答

1，在void outprint(void)，更改

printf(" %c | %c | %c \n" , board[r][0], board[r][2], board[r][3]);

成

printf(" %c | %c | %c \n" , board[r][0], board[r][1], board[r][2]);

2，在int main(void)，更改int win;成int win = 0;

我的程序的逻辑有什么问题？

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