怎样才能获得价值PreferenceFragment

Question

我有这样的代码：

<?xml version="1.0" encoding="utf-8"?> 
<PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android"> 
    <CheckBoxPreference android:key="notification_settings" 
     android:text="@string/impostazione" 
     android:id="@+id/save_check" 
     android:summary="@string/notification_title" 
     android:defaultValue="false" 

     ></CheckBoxPreference> 

</PreferenceScreen> 

现在我需要在FragmentA得到复选框值：

sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity()); 

现在？

Answer 1

试试这个办法，希望这将帮助你解决你的问题。

sharedPreferences.getBoolean("notification_settings",false) 

getBoolean()：需要两个参数一个是关键，一个是默认值

Answer 2

sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity()); 
boolean isChecked = sharedPreferences.getBoolean(getString(R.string.notification_settings), false); 

Answer 3

strings.xml 
<string name="notification_setting">notification_settings</string> 
--------------------------------- 
xxx.xml 
..... 
<CheckBoxPreference android:key="@string/notification_setting" 
.... 
-------------------------------- 
.java 
sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getActivity()); 
boolean wifiState = sharedPreferences.getBoolean(R.string.setting_wifi_key, false); 

wifiState is you value.