如何将检查值和变量值推送到json数组
这里我有一个表单，一个表单域是复选框，假设我点击病房长袍&灯光并点击提交按钮表示我正在使用这个价值和推到我的JSON格式到现在它工作正常，我的问题是我必须变量假设在该变量！空意味着我想推入这个值到我的json.one更多的条件，我们必须检查，就像我想在形式我点击数值是病房长袍&冰箱和我的var needtopushval ='冰箱'; Fride是两个时间是如此不应该这样varaible推到我的JSON如何将检查值和变量值推送到json数组
function rentfunction(){
var needtopushval=' Lights';
var arr1 = [];
var data={
"rentProperty": {
"fullName" : "Some Name"
},
"floorType":[]
};
$.each($("input[name='furniture_check']:checked"),function(){
var furniture = $(this).val();
arr1.push({"floorTypeName": furniture });
});
arr1.push({"floorTypeName": needtopushval });
data.floorType=arr1;
//or data["floorType"]=arr1;
console.log(data);
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<form>
\t <input type="checkbox" name="furniture_check" value="Ward robe">Ward robe <br>
\t <input type="checkbox" name="furniture_check" value="Lights">Lights <br>
\t <input type="checkbox" name="furniture_check" value="Fan">Fan <br><br><br>
<button type="button" id="rentBtnSubmit" onclick="rentfunction()">Submit</button>
</form>我的预期JSON
{
"rentProperty": {
"fullName": "Some Name"
},
"floorType": [
{
"floorTypeName": "Ward robe"
},
{
"floorTypeName": "Lights"
},
{
"floorTypeName": "Fridge"
}
]
}
我希望它会帮助你解决您的问题
function rentfunction(){
var needtopushval='Lights';
var arr1 = [];
var data={
"rentProperty": {
"fullName" : "Some Name"
},
"floorType":[]
};
//
$.each($("input[name='furniture_check']:checked"),function(e) {
var furniture = $.trim($(this).val());
var index=data.floorType.indexOf({"floorTypeName": furniture });
if(index==-1){
data.floorType.push({"floorTypeName": furniture });
}
});
var flag=0;
$.each(data.floorType,function(e){
if($.trim(data.floorType[e].floorTypeName) === $.trim(needtopushval)){
flag=1;
}
});
if(flag==0){
data.floorType.push({"floorTypeName": $.trim(needtopushval)});
}
console.log(data);
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<form>
\t <input type="checkbox" name="furniture_check" value="Ward robe">Ward robe <br>
\t <input type="checkbox" name="furniture_check" value="Lights">Lights <br>
\t <input type="checkbox" name="furniture_check" value="Fan">Fan <br><br><br>
<button type="button" id="rentBtnSubmit" onclick="rentfunction()">Submit</button>
</form>不正确，因为假设我选择Ward robe＆Fan意味着我们必须推var var needtopushval ='Lights';答案应该来这样 { “rentProperty”：{ “全名”： “有些名称” }， “floorType”： { “floorTypeName”： “沃德袍” }， { “floorTypeName “： “清香” }，{ “floorTypeName”： “范” } ] } –
@RohitM我已经更新了我的答案 –
希望下面的代码可以帮助
代码来检查非空值和天气的价值已经存在
var pos = arr1.map(function(e) {
return e.floorTypeName;
}).indexOf(furniture);
if (pos == -1 && needtopushval) {
arr1.push({
"floorTypeName": needtopushval
});
}
function rentfunction() {
var needtopushval = ' Lights';
var arr1 = [];
var data = {
"rentProperty": {
"fullName": "Some Name"
},
"floorType": []
};
$.each($("input[name='furniture_check']:checked"), function() {
var furniture = $(this).val();
if (furniture) {
arr1.push({
"floorTypeName": furniture
});
}
//Code to Check weather a value exist and notempty
var pos = arr1.map(function(e) {
return e.floorTypeName;
}).indexOf(furniture);
if (pos == -1 && needtopushval) {
arr1.push({
"floorTypeName": needtopushval
});
}
});
data.floorType = arr1;
//or data["floorType"]=arr1;
console.log(data);
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<form>
\t <input type="checkbox" name="furniture_check" value="Ward robe">Ward robe <br>
\t <input type="checkbox" name="furniture_check" value="Lights">Lights <br>
\t <input type="checkbox" name="furniture_check" value="Fan">Fan <br><br><br>
<button type="button" id="rentBtnSubmit" onclick="rentfunction()">Submit</button>
</form>
您可以使用这个'data.floorType.push（{__YOUR_OBJECT __}）' –
Rohit将对象直接推送到'floorType'，因为您的问题*我的问题*不清楚。你可以换个不同的方式，也许在两个不同的段落中有例子输入/输出吗？ – gurvinder372
@SK Jajoriya，是的正确我实施检查我的代码片段，主要问题是在表单字段我正在检查灯光和我的needtopushval也灯光所以两个时间相同的价值推动对象，但对我来说只需要一次只推值 –