不发送消息

Question

嗨我使用此代码发送任何号码的短信，但它是第一次工作，并没有下一次。任何修复？ MY_PERMISSION_REQUEST_SEND_SMS中有问题吗？有没有其他简短的方法发送短信？

public class MainActivity extends AppCompatActivity { 
private static final int MY_PERMISSIONS_REQUEST_SEND_SMS =0 ; 
String phonenumber; 
EditText number; 
String message; 
Button btn; 
EditText txt; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 


    btn = (Button) findViewById(R.id.send); 
    txt = (EditText) findViewById(R.id.message); 
    number = (EditText) findViewById(R.id.Number); 

    btn.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 
      SendSms(); 

     } 

    }); 
} 

protected void SendSms() { 
    phonenumber=number.getText().toString(); 
    message= txt.getText().toString(); 
    if (ContextCompat.checkSelfPermission(this, 
      Manifest.permission.SEND_SMS) 
      != PackageManager.PERMISSION_GRANTED) { 
     if (ActivityCompat.shouldShowRequestPermissionRationale(this, 
       Manifest.permission.SEND_SMS)) { 
     } else { 
      ActivityCompat.requestPermissions(this, 
        new String[]{Manifest.permission.SEND_SMS}, 
        MY_PERMISSIONS_REQUEST_SEND_SMS); 

     } 
    } 

} 
@Override 
public void onRequestPermissionsResult(int requestCode,String permissions[], 
    int[] grantResults) { 
    switch (requestCode) { 
     case MY_PERMISSIONS_REQUEST_SEND_SMS: { 
      if (grantResults.length > 0 
        && grantResults[0] == PackageManager.PERMISSION_GRANTED)  
     { 
       SmsManager smsManager = SmsManager.getDefault(); 
       smsManager.sendTextMessage(phonenumber, null, message, null, 
     null); 
       Toast.makeText(getApplicationContext(), "SMS sent.", 
         Toast.LENGTH_LONG).show(); 
      } else { 
       Toast.makeText(getApplicationContext(), 
         "SMS faild, please try again.", 
     Toast.LENGTH_LONG).show(); 
       return; 
      } 
     } 
    } 

} 
} 

Answer 1

你不具备条件时，你已经拥有的访问发送短信的权限

否则将用于外，如果和执行你发送短信代码

Answer 2

这是因为你错过了来电smsManager发送短信，如果允许授予
做出更好的方法，

private void smsSend(){ 
SmsManager smsManager = SmsManager.getDefault(); 
      smsManager.sendTextMessage(phonenumber, null, message, null, 
    null); 
      Toast.makeText(getApplicationContext(), "SMS sent.", 
        Toast.LENGTH_LONG).show(); 
} 

if (ContextCompat.checkSelfPermission(this, 
     Manifest.permission.SEND_SMS) 
     != PackageManager.PERMISSION_GRANTED) { 
    if (ActivityCompat.shouldShowRequestPermissionRationale(this, 
      Manifest.permission.SEND_SMS)) { 
    } else { 
     ActivityCompat.requestPermissions(this, 
       new String[]{Manifest.permission.SEND_SMS}, 
       MY_PERMISSIONS_REQUEST_SEND_SMS); 

    } 
} 
else{ 
    smsSend(); //call method if already granted 
} 

，并呼吁烫发后，这种方法ission授予也，

@Override 
    public void onRequestPermissionsResult(int requestCode,String permissions[], 
    int[] grantResults) { 
    switch (requestCode) { 
     case MY_PERMISSIONS_REQUEST_SEND_SMS: { 
      if (grantResults.length > 0 
       && grantResults[0] == PackageManager.PERMISSION_GRANTED)  
      { 
       smsSend(); //call method after permission grant 
      } else { 
       Toast.makeText(getApplicationContext(), 
        "SMS faild, please try again.", 
    Toast.LENGTH_LONG).show(); 
       return; 
      } 
     } 
    } 

}