获取网页的内容，并比较

Question

可以有人帮忙/纠正我写一个shell脚本，这里是我想要做的网页

• 获取内容
• 比较内容
• 如果内容相同则返回0
• 如果不返回2

这里是我的代码

for cluster in $CLUSTERS 
do 
    for applis in $(eval echo \$${cluster}_APPLIS) 
    do 
     CONTENT=$(wget -q -O - "http://$server/$applis") 
     if [ "$CONTENT" -eq 1 ] 
     then 
     exit_code=0 
     else 
     exit_code=2 
     fi 
    done 
done 

[[ -z "$error_server" ]] && error_server="aucune" 

case $exit_code in 
    "2") 
      echo "CRITICAL - App Version Mismatch" 
      exit 2 
      ;; 
    "1") 
      echo "WARNING - instance(s) indisponible(s)" 
      exit 1 
      ;; 
    "0") 
      echo "OK - All apps have the save version" 
      exit 0 
      ;; 
    *) 
      echo "CRITICAL - there's something wrong with this script ..." 
      exit 2 
      ;; 
esac 

任何帮助或建议，将不胜感激

问候 的Fab

Answer 1

您可以使用diff来比较文件的两个版本。第一个变量用于获取网页的第一个版本。我不确定是首先应该在第一个循环内还是外部初始化。

first=1 
for cluster in $CLUSTERS 
do 
    for applis in $(eval echo \$${cluster}_APPLIS) 
    do 
     if [ $first -eq 1 ];then 
      first=0 
      PREV_CONTENT=$(wget -q -O - "http://$server/$applis") 
     else 
      CONTENT=$(wget -q -O - "http://$server/$applis") 
      diff $PREV_CONTENT $CONTENT 
      PREV_CONTENT=$CONTENT 
      result=$? 
     fi 
     if [ "$result" -eq 0 ] 
     then 
      exit_code=0 
     else 
      exit_code=2 
     fi 
    done 

做