无法获取网页的源代码

Question

我正在尝试使用Java从此网站获取HTML页面源内容：“http://207.200.96.231:8008”。但是默认的Java库并没有帮助我。我也尝试使用这个tutorial，但它也没有工作。我认为问题是由于网站的安全保护而发生的。当我运行下面提供的以下代码时，我得到一个异常：java.io.IOException: Invalid Http response。

有关如何实现代码的任何想法？还是有任何图书馆可以满足我的需求？到目前为止，我已经尝试JSoup和Jericho HTML解析器认为他们会使用不同的方法连接到我提供的站点，但他们也失败了。

String urlstr = "http://72.26.204.28:9484/played.html"; 

try { 

    URL url = new URL(urlstr); 

    URLConnection urlc = url.openConnection(); 

    InputStream stream = urlc.getInputStream(); 
    BufferedInputStream buf = new BufferedInputStream(stream); 

    StringBuilder sb = new StringBuilder(); 

    while (true){ 

    int data = buf.read(); 

    if (data == -1) 
     break; 
    else 
     sb.append((char)data); 
    } 

    } catch (MalformedURLException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
} 

EDIT（问题解决）：随着Karai17和trashgod帮助我设法解决这个问题。 Shoutcast页面需要用户代理才能访问其内容。所以我们需要做的是添加以下代码：

urlConnection.setRequestProperty("User-Agent", "Mozilla/5.0"); 

最新的代码如下所示：

try { 
     URL url = new URL("http://207.200.96.231:8008/7.html"); 
     HttpURLConnection urlConnection = (HttpURLConnection)url.openConnection(); 
     urlConnection.setRequestProperty("User-Agent", "Mozilla/5.0"); 

     InputStream is = urlConnection.getInputStream(); 
     BufferedInputStream in = new BufferedInputStream(is); 
     int c; 
     while ((c = in.read()) != -1) { 
      System.out.write(c); 
     } 
     urlConnection.disconnect(); 
    } catch (MalformedURLException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
} 

Answer 1

这流似乎需要Winamp。

 
$ curl -v http://207.200.96.231:8008 
* About to connect() to 207.200.96.231 port 8008 (#0) 
* Trying 207.200.96.231... connected 
* Connected to 207.200.96.231 (207.200.96.231) port 8008 (#0) 
It appears to require [Winamp][2]. 

> GET/HTTP/1.1 
> User-Agent: curl/... 
> Host: 207.200.96.231:8008 
> Accept: */* 
> 
ICY 200 OK 
icy-notice1:
This stream requires Winamp
 
icy-notice2:SHOUTcast Distributed Network Audio Server/Linux v1.9.93atdn
 
icy-name:Absolutely Smooth Jazz - SKY.FM - the world's smoothest jazz 24 hours a day 
icy-genre:Soft Smooth Jazz 
icy-url:http://www.sky.fm/smoothjazz/ 
content-type:audio/mpeg 
icy-pub:1 
icy-br:96 
... 

附录：可以读取流是这样的：

URL url = new URL("http://207.200.96.231:8008"); 
URLConnection con = url.openConnection(); 
InputStream is = con.getInputStream(); 
BufferedInputStream in = new BufferedInputStream(is); 
int c; 
while ((c = in.read()) != -1) { 
    System.out.write(c); 
}